**Educational Explanation of the Circuit Diagram****Circuit Description:**The diagram depicts an NPN transistor circuit with a given supply voltage of +15 V. The transistor is operated in active mode, with specific resistors and voltage sources placed in the circuit as follows:- **Resistors:** - A 100 kΩ resistor is connected to the base of the transistor. - An 18 kΩ resistor is connected in series with the 100 kΩ resistor and the ground. - A 6.4 kΩ resistor is connected to the collector of the transistor. - A 750 Ω resistor is connected to the emitter of the transistor.- **Transistor Parameters:** - The base-emitter voltage (\(V_{BE}\)) is assumed to be 0.7 V. - The transistor's current gain (\(\beta\)) is 100.- **Currents and Voltages:** - \(I_B\) is the base current entering the transistor. - \(I_C\) is the collector current. - \(V_{CE}\) is the voltage across the collector and emitter of the transistor.**Objective:**Find the values of base current (\(I_B\)), collector current (\(I_C\)), and collector-emitter voltage (\(V_{CE}\)).**Analysis Approach:**1. **Base Current (\(I_B\)):** - The voltage at the base is determined using the voltage divider rule across the 100 kΩ and 18 kΩ resistors. - Subtract \(V_{BE}\) to find the voltage across the 18 kΩ resistor and calculate \(I_B\) using Ohm's Law.2. **Collector Current (\(I_C\)):** - Use the relation \(I_C = \beta \cdot I_B\).3. **Collector-Emitter Voltage (\(V_{CE}\)):** - Apply Kirchhoff’s Voltage Law around the collector-emitter loop to find \(V_{CE}\).This analysis allows the determination of the specific currents and voltage in this transistor circuit setup, useful for understanding its behavior in active mode.

In this question, we need to determine the base current, collector current and voltage VCE as shown in the circuit. IB = 17.46 uAIC = 1.736 mAVCE = 2.574 V

Answered: 100 ΚΩ 18 ΚΩ ww +15 V IB + VBE C 6.4 ΚΩ…

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100 ΚΩ 18 ΚΩ ww +15 V IB + VBE C 6.4 ΚΩ + VCE 750 Ω Find the values of IB, IC and VCE for the circuit shown. The transistor is in active mode; assume VBE = 0.7 V and B = 100

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

**Educational Explanation of the Circuit Diagram**

**Circuit Description:**

The diagram depicts an NPN transistor circuit with a given supply voltage of +15 V. The transistor is operated in active mode, with specific resistors and voltage sources placed in the circuit as follows:

- **Resistors:**
- A 100 kΩ resistor is connected to the base of the transistor.
- An 18 kΩ resistor is connected in series with the 100 kΩ resistor and the ground.
- A 6.4 kΩ resistor is connected to the collector of the transistor.
- A 750 Ω resistor is connected to the emitter of the transistor.

- **Transistor Parameters:**
- The base-emitter voltage (\(V_{BE}\)) is assumed to be 0.7 V.
- The transistor's current gain (\(\beta\)) is 100.

- **Currents and Voltages:**
- \(I_B\) is the base current entering the transistor.
- \(I_C\) is the collector current.
- \(V_{CE}\) is the voltage across the collector and emitter of the transistor.

**Objective:**

Find the values of base current (\(I_B\)), collector current (\(I_C\)), and collector-emitter voltage (\(V_{CE}\)).

**Analysis Approach:**

1. **Base Current (\(I_B\)):**
- The voltage at the base is determined using the voltage divider rule across the 100 kΩ and 18 kΩ resistors.
- Subtract \(V_{BE}\) to find the voltage across the 18 kΩ resistor and calculate \(I_B\) using Ohm's Law.

2. **Collector Current (\(I_C\)):**
- Use the relation \(I_C = \beta \cdot I_B\).

3. **Collector-Emitter Voltage (\(V_{CE}\)):**
- Apply Kirchhoff’s Voltage Law around the collector-emitter loop to find \(V_{CE}\).

This analysis allows the determination of the specific currents and voltage in this transistor circuit setup, useful for understanding its behavior in active mode.

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