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100 20o A. 10 ohms 6 V B. 9 ohms 202 102 C. 5 ohms

100 20o A. 10 ohms 6 V B. 9 ohms 202 102 C. 5 ohms

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer the question listed below and select the correct answer choices below. Thank you! 

**Problem Statement:** What is the equivalent resistance to the three resistors in the figure? **Options:** - A. 10 ohms - B. 9 ohms - C. 5 ohms - D. 4 ohms **Diagram Explanation:** The diagram illustrates a circuit containing three resistors. Here’s a breakdown: 1. **Left Section of the Circuit:** - Two resistors are connected in parallel: 10 ohms and 20 ohms. 2. **Right Section of the Circuit:** - Another parallel configuration with resistors: 10 ohms and 20 ohms. 3. The circuit is powered by a 6 V battery. **Analysis:** To find the equivalent resistance: 1. Calculate the parallel resistances for each section: - For both sections, using the formula for parallel resistors \( R_{\text{eq}} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2}} \): - \( R_{\text{eq, left}} = \frac{1}{\frac{1}{10} + \frac{1}{20}} \) = 6.67 ohms (approximately) - \( R_{\text{eq, right}} = \frac{1}{\frac{1}{10} + \frac{1}{20}} \) = 6.67 ohms (approximately) 2. Since the left and right equivalents are connected in series: - Total \( R_{\text{eq}} = R_{\text{eq, left}} + R_{\text{eq, right}} = 6.67 + 6.67 = 13.34 \) ohms Thus, the solution would not match any of the given options directly, indicating potential typographical or calculation error, or misinterpretation of connection type. However, upon reevaluation using alternative or hypothetical assumptions based on discrepancies: - Reinterpreting resistances or reevaluating steps for precise and congruent option matching could rectify. On an educational site, provide student engagement solutions such as explorations of assumptions, common calculation pitfalls, and their possible corrections.
Transcribed Image Text:**Problem Statement:** What is the equivalent resistance to the three resistors in the figure? **Options:** - A. 10 ohms - B. 9 ohms - C. 5 ohms - D. 4 ohms **Diagram Explanation:** The diagram illustrates a circuit containing three resistors. Here’s a breakdown: 1. **Left Section of the Circuit:** - Two resistors are connected in parallel: 10 ohms and 20 ohms. 2. **Right Section of the Circuit:** - Another parallel configuration with resistors: 10 ohms and 20 ohms. 3. The circuit is powered by a 6 V battery. **Analysis:** To find the equivalent resistance: 1. Calculate the parallel resistances for each section: - For both sections, using the formula for parallel resistors \( R_{\text{eq}} = \frac{1}{\frac{1}{R_1} + \frac{1}{R_2}} \): - \( R_{\text{eq, left}} = \frac{1}{\frac{1}{10} + \frac{1}{20}} \) = 6.67 ohms (approximately) - \( R_{\text{eq, right}} = \frac{1}{\frac{1}{10} + \frac{1}{20}} \) = 6.67 ohms (approximately) 2. Since the left and right equivalents are connected in series: - Total \( R_{\text{eq}} = R_{\text{eq, left}} + R_{\text{eq, right}} = 6.67 + 6.67 = 13.34 \) ohms Thus, the solution would not match any of the given options directly, indicating potential typographical or calculation error, or misinterpretation of connection type. However, upon reevaluation using alternative or hypothetical assumptions based on discrepancies: - Reinterpreting resistances or reevaluating steps for precise and congruent option matching could rectify. On an educational site, provide student engagement solutions such as explorations of assumptions, common calculation pitfalls, and their possible corrections.
Expert Solution
Step 1

There are two sets of parallel resistance .These equivalent resistance for both the sets are in series with each other.

For parallel resistance, to the left side of the positive terminal,

R'=1110+120+110

R'=205

R'=4 ohm

 

The Equivalent resistance to the right side of the negative terminal,

R''=1120+110+120

R''=5 ohm

 

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