10.58 A 50.0 kg grindstone is a solid disk 0.520 m in diam-eter. You press an ax down on the rim with a normal force of 160 N(Fig. P10.58). The coefficient of kinetic friction between the blade andthe stone is 0.60, and there is a constant friction torque of 6.50 N mbetween the axle of the stone and its bearings. (a) How much force mustbe applied tangentially at the end of a crank handle 0.500 m long tobring the stone from rest to 120 rev/min in 9.00 s? (b) After the grind-stone attains an angular speed of 120 rev/min, what tangential force atthe end of the handle is needed to maintain a constant angular speed of120 rev/min? (c) How much time does it take the grindstone to comefrom 120 rev/min to rest if it is acted on by the axle friction alone?Figure P10.5850.0 kgm =F 160 N

1 concept and principles1‐Rotational Acceleration α the average rotational acceleration αalhpa of…

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