10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: СНЗСООН + NaOH > CHЗСОONa + Н20 (M.W of Acetic acid = 60 g*mol, Density of Vinegar = 1.05 g/ml) %3D Calculate Mass % of acetic acid. 1% 2% 3% 4%
10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: СНЗСООН + NaOH > CHЗСОONa + Н20 (M.W of Acetic acid = 60 g*mol, Density of Vinegar = 1.05 g/ml) %3D Calculate Mass % of acetic acid. 1% 2% 3% 4%
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.8: Stoichiometry Of Reactions In Aqueous Solution-titrations
Problem 4.12CYU: An unknown monoprotic acid reacts with NaOH according to the net ionic equation HA(aq) + OH(aq) ...
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![10.00 ml of acetic acid was titrated
with 35.00 ml of 0.10 M NaOH solution,
according to the following equation:
СНЗСООН + NaOH > CHЗСОONa +
H20
(M.W of Acetic acid = 60 g*mol, Density
of Vinegar = 1.05 g/ml)
Calculate Mass % of acetic acid.
1%
2%
3%
4%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe914ac87-2240-4cd4-831d-e68f6d0498ea%2F1decb630-28a9-4ce8-8eea-15f46470913e%2Fxlnwzw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10.00 ml of acetic acid was titrated
with 35.00 ml of 0.10 M NaOH solution,
according to the following equation:
СНЗСООН + NaOH > CHЗСОONa +
H20
(M.W of Acetic acid = 60 g*mol, Density
of Vinegar = 1.05 g/ml)
Calculate Mass % of acetic acid.
1%
2%
3%
4%
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