10.00 ml of acetic acid was titratedwith 35.00 ml of 0.10 M NaOH solution,according to the following equation:СНЗСООН + NaOH > CHЗСОONa +H20(M.W of Acetic acid = 60 g*mol, Densityof Vinegar = 1.05 g/ml)Calculate Mass % of acetic acid.1%2%3%4%

Interpretation - To calculate the percentage mass of acetic acid when 10 mL of acetic acid was…

10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: СНЗСООН + NaOH > CHЗСОONa + Н20 (M.W of Acetic acid = 60 g*mol, Density of Vinegar = 1.05 g/ml) %3D Calculate Mass % of acetic acid. 1% 2% 3% 4%

10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: СНЗСООН + NaOH > CHЗСОONa + Н20 (M.W of Acetic acid = 60 g*mol, Density of Vinegar = 1.05 g/ml) %3D Calculate Mass % of acetic acid. 1% 2% 3% 4%

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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100%

10.00 ml of acetic acid was titrated
with 35.00 ml of 0.10 M NaOH solution,
according to the following equation:
СНЗСООН + NaOH > CHЗСОONa +
H20
(M.W of Acetic acid = 60 g*mol, Density
of Vinegar = 1.05 g/ml)
Calculate Mass % of acetic acid.
1%
2%
3%
4%

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