10. z Scores: Fawns Fawns between 1 and 5 months old in Mesa Verde National Park have a body weight that is approximately normally distributed with mean μ = 27.2 kilograms and standard deviation = 4.3 kilograms (based on in- formation from The Mule Deer of Mesa Verde National Park, by G. W. Mierau and J. L. Schmidt, Mesa Verde Museum Association). Let x be the weight of a fawn in kilograms. Convert each of the following x intervals to z intervals. (a) r < 30 (b) 19 < x (c) 32
10. z Scores: Fawns Fawns between 1 and 5 months old in Mesa Verde National Park have a body weight that is approximately normally distributed with mean μ = 27.2 kilograms and standard deviation = 4.3 kilograms (based on in- formation from The Mule Deer of Mesa Verde National Park, by G. W. Mierau and J. L. Schmidt, Mesa Verde Museum Association). Let x be the weight of a fawn in kilograms. Convert each of the following x intervals to z intervals. (a) r < 30 (b) 19 < x (c) 32
MATLAB: An Introduction with Applications
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Please answer number 10. Make sure to answer all parts!!! Please answer all parts to the question. If you can’t then please answer parts d to h.
Transcribed Image Text:10. z Scores: Fawns Fawns between 1 and 5 months old in Mesa Verde National
Park have a body weight that is approximately normally distributed with mean
μ = 27.2 kilograms and standard deviation r = 4.3 kilograms (based on in-
formation from The Mule Deer of Mesa Verde National Park, by G. W. Mierau
and J. L. Schmidt, Mesa Verde Museum Association). Let x be the weight of a
fawn in kilograms. Convert each of the following x intervals to z intervals.
(a) x < 30 (b) 19 < x (c) 32 < x < 35
right 2019 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. WCN 02-200-203
e Learning. All Rights Reserved. May not be copied, scanned, or d
that any suppressed contentslompostela
azaldu
SECTION 7:2
ander Chapter(s).
the Standard Normal Distribution
Convert each of the following z intervals to x intervals.
(d) - 2.17<z (e) z < 1.28 (f) 1.99<z < 1.44
(g) Interpretation If a fawn weighs 14 kilograms, would you say it is an
unusually small animal? Explain using z values and Figure 7-12.
(h) Interpretation If a fawn is unusually large, would you say that the z
value for the weight of the fawn will be close to 0, -2, or 3? Explain.
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