10. Which probability distribution represents the given problem? A. 0. 1 С. 1 1 1 3 3. 1 P(X) P(X) 4 8. 8. В. D. 3 3. 35 P(X) 4 P(X) 8. 8. 8 11. Which of the following values can serve as the values of a probability distribution? A. P(1) B. P(1) = 9/14, P(2) С. Р(1) D. P(1) 12. The probabilities that a customer buys 5, 8, 9, 12, and 15 items in a grocery store are 0.06, 0.14, 0.32, 0.28, and 0.20, respectively. Which probability distribution represents the given problem? 0.42, P(2) 0.31, P(3) = 0.37 4/14, P(3) = 1/14 0.12, P(3) = 1.03 12/33, P(3) = 10/33 %3D %3D %3D %3D 0.08, P(2) 10/33, P(2) = %3D %3D 8. 9. 12 15 A. P(X) 0.06 0.14 0.2 0.28 0.32 9. 12 15 P(X) 0.32 0.28 0.2 0.14 0.06 8. 9. 12 15 С. 0.14 0.32 0.28 0.20 P(X) 0.06 9. 12 15 D. 0.28 0.32 0.14 0.2 P(X) 0.06 1118 00 2114 1112 B. B.

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Chapter1: Combinatorial Analysis
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Answer the following,choice the letter of the correct answer.

10. Which probability distribution represents the given problem?
A.
С.
0.
1
1
P(X)
4
P(X)
В.
D.
0.
1
1
3.
35
P(X)
4
4
P(X)
8.
8.
11. Which of the following values can serve as the values of a probability
distribution?
A. P(1)
= 0.42, P(2)
0.31, P(3) = 0.37
%3D
%3D
B. P(1) = 9/14, P(2) = 4/14, P(3) = 1/14
С. Р(1)
D. P(1)
%3D
0.08, P(2) = 0.12, P(3) = 1.03
= 12/33, P(3)
%3D
%3D
%3D
10/33, P(2)
10/33
%3D
%3D
12. The probabilities that a customer buys 5, 8, 9, 12, and 15 items in a
grocery store are 0.06, 0.14, 0.32, 0.28, and 0.20, respectively. Which
probability distribution represents the given problem?
8
6.
12
15
A.
P(X)
0.06
0.14
0.2
0.28
0.32
8.
6.
12
15
P(X)
0.32
0.28
0.2
0.14
0.06
8.
6.
12
15
5.
0.14
0.32
0.28
0.20
P(X)
0.06
6.
12
15
8.
D.
0.28
0.32
0.06
0.14
0.2
P(X)
3118
31100
2318
13/8
1118
8/88
1112
1112
112
B.
C.
Transcribed Image Text:10. Which probability distribution represents the given problem? A. С. 0. 1 1 P(X) 4 P(X) В. D. 0. 1 1 3. 35 P(X) 4 4 P(X) 8. 8. 11. Which of the following values can serve as the values of a probability distribution? A. P(1) = 0.42, P(2) 0.31, P(3) = 0.37 %3D %3D B. P(1) = 9/14, P(2) = 4/14, P(3) = 1/14 С. Р(1) D. P(1) %3D 0.08, P(2) = 0.12, P(3) = 1.03 = 12/33, P(3) %3D %3D %3D 10/33, P(2) 10/33 %3D %3D 12. The probabilities that a customer buys 5, 8, 9, 12, and 15 items in a grocery store are 0.06, 0.14, 0.32, 0.28, and 0.20, respectively. Which probability distribution represents the given problem? 8 6. 12 15 A. P(X) 0.06 0.14 0.2 0.28 0.32 8. 6. 12 15 P(X) 0.32 0.28 0.2 0.14 0.06 8. 6. 12 15 5. 0.14 0.32 0.28 0.20 P(X) 0.06 6. 12 15 8. D. 0.28 0.32 0.06 0.14 0.2 P(X) 3118 31100 2318 13/8 1118 8/88 1112 1112 112 B. C.
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