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10. What is the range _sxs_) of the data values that would allow 71% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. • D100 EN t LOG THE RANGE OF THt DATA GALUES TT A S r TO PALL N MAN EENNG The range of data values that will allow 71% of the data to fall within the mean of symmetry is - 0.2552 and 4.2552. 11. What is the variance of this data set? o? = (2.1275)? o² = 4.5263 Given that the standard deviation is 2.1275 and it is the square root of the variance, the value of the variance is 4.5263. 12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). There is only one outlier with this data set (i.e. 9) while the remaining values in the data set do not go beyond the three standard deviations from the mean.

10. What is the range _sxs_) of the data values that would allow 71% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. • D100 EN t LOG THE RANGE OF THt DATA GALUES TT A S r TO PALL N MAN EENNG The range of data values that will allow 71% of the data to fall within the mean of symmetry is - 0.2552 and 4.2552. 11. What is the variance of this data set? o? = (2.1275)? o² = 4.5263 Given that the standard deviation is 2.1275 and it is the square root of the variance, the value of the variance is 4.5263. 12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). There is only one outlier with this data set (i.e. 9) while the remaining values in the data set do not go beyond the three standard deviations from the mean.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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10. What is the range (sxS_) of the data values that would allow 71% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. The Normal Distribution Activity For Data Set 3 A. 717. • 0.100 Variance = A: : 0. J55; e1.06 Mean = 8.33 0.8427 Standard Deviation = 0,9180 WHEN LOG THE RANGE OF THE ĐATA UALUES 13. Sketch the third bell curve by showing the mean and standard deviation. Surt 1.1561.. TO PALL TNIN TNE MEAN ORJEENG -1. 1 *.st -1.G 16 The range of data values that will allow 71% of the data to fall within the mean of symmetry is 0.2552 and 4.2552. 11. What is the variance of this data set? o? = (2.1275)? o? = 4.5263 Given that the standard deviation is 2.1275 and it is the square root of the variance, 1. N . .n4 the value of the variance is 4.5263. 12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). 14. What are the data values (raw scores) associated with standard scores of -1.05 and -0.05? Determine the percentage in between these scores. Draw the curve and show your complete solution. There is only one outlier with this data set (i.e. 9) while the remaining values in the data set do not go beyond the three standard deviations from the mean. -0. I -I. THE PECENTAE en . The percentage that is in between the raw scores of 7.3661 and 8.2841 is 33.32%. 15. What are the data values (raw scores) associated with standard scores of -0.09 and 1.15? Determine the percentage in between these scores. Draw the curve and show your complete solution. A.0.ceco.n 0. gire I-oss -t * 9. JES LIS The percentage that is in between the raw scores of 8.2474 and 9.3857 is 33.9%.
Transcribed Image Text:10. What is the range (sxS_) of the data values that would allow 71% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. The Normal Distribution Activity For Data Set 3 A. 717. • 0.100 Variance = A: : 0. J55; e1.06 Mean = 8.33 0.8427 Standard Deviation = 0,9180 WHEN LOG THE RANGE OF THE ĐATA UALUES 13. Sketch the third bell curve by showing the mean and standard deviation. Surt 1.1561.. TO PALL TNIN TNE MEAN ORJEENG -1. 1 *.st -1.G 16 The range of data values that will allow 71% of the data to fall within the mean of symmetry is 0.2552 and 4.2552. 11. What is the variance of this data set? o? = (2.1275)? o? = 4.5263 Given that the standard deviation is 2.1275 and it is the square root of the variance, 1. N . .n4 the value of the variance is 4.5263. 12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). 14. What are the data values (raw scores) associated with standard scores of -1.05 and -0.05? Determine the percentage in between these scores. Draw the curve and show your complete solution. There is only one outlier with this data set (i.e. 9) while the remaining values in the data set do not go beyond the three standard deviations from the mean. -0. I -I. THE PECENTAE en . The percentage that is in between the raw scores of 7.3661 and 8.2841 is 33.32%. 15. What are the data values (raw scores) associated with standard scores of -0.09 and 1.15? Determine the percentage in between these scores. Draw the curve and show your complete solution. A.0.ceco.n 0. gire I-oss -t * 9. JES LIS The percentage that is in between the raw scores of 8.2474 and 9.3857 is 33.9%.
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