What is the answer for the attached question ?Thanks Certainly! Here is the transcription for the educational website:---**10. Use the formula**\[\sum_{k=1}^{n} (3k-1)(k-4) = n^3 - 5n^2 - 2n, \quad \forall \, n \in \mathbb{Z}^+\]**to calculate**the sum \((-6) + (-10) + (-8) + 0 + \ldots + 840 + 944\) \[= \sum_{k=1}^{20} (3k-1)(k-4).\]---**Explanation:**This mathematical problem involves using a formula to calculate a specific sum of terms. The formula involves evaluating the expression \((3k-1)(k-4)\) for each integer \(k\) from 1 to \(n\), then summing the results. The formula simplifies this sum to the expression \(n^3 - 5n^2 - 2n\), which can be used to find the sum directly for any positive integer \(n\).In the problem, you are asked to calculate the sum of terms from \((-6) + (-10) + (-8) + 0 + \ldots + 840 + 944\), which corresponds to \(\sum_{k=1}^{20} (3k-1)(k-4)\).**Note:**- The notation \(\mathbb{Z}^+\) denotes the set of all positive integers.- The summation index starts at \(k=1\) and goes up to \(n=20\) in this particular problem.This allows for a simplified way of calculating complex sums using known algebraic identities.

Name: What is the answer for the attached question ?Thanks Certainly! Here i
Uploaded: 2024-03-20T07:07:37.000Z
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Description: What is the answer for the attached question ?Thanks Certainly! Here is the transcription for the educational website:---**10. Use the formula**\[\sum_{k=1}^{n} (3k-1)(k-4) = n^3 - 5n^2 - 2n, \quad \forall \, n \in \mathbb{Z}^+\]**to calculate**the s