10. The ages of the population of a town are normally distributed with mean 43 and standard deviation 14. The town has a population of 5,000. How many would you expect to be aged between 22 and 57? Use the following Standard Normal Distribution curve: 19.1% 19.1% 15.0% 15.0% 9.2% 9.2% 0.1% 0.5% 4.4% 1.7% 0.5% 0.1% 4.4% 1.7% -3 -2.5 -2 -1.5 -1 -0.5 0.5 1 1.5 2 2.5 3

MATLAB: An Introduction with Applications
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**Problem Statement:**

The ages of the population of a town are normally distributed with a mean of 43 and a standard deviation of 14. The town has a population of 5,000. How many would you expect to be aged between 22 and 57?

**Solution Approach:**

To solve this, use the provided Standard Normal Distribution curve.

**Graph Explanation:**

The graph is a bell-shaped curve, typical of a standard normal distribution, with the mean at the center (0) and standard deviations marked along the x-axis from -3 to 3. The percentages in the graph represent the proportion of the population within each segment:

- From -3 to -2.5: 0.1%
- From -2.5 to -2: 0.5%
- From -2 to -1.5: 1.7%
- From -1.5 to -1: 4.4%
- From -1 to -0.5: 9.2%
- From -0.5 to 0: 15.0%
- From 0 to 0.5: 19.1%
- From 0.5 to 1: 19.1%
- From 1 to 1.5: 15.0%
- From 1.5 to 2: 9.2%
- From 2 to 2.5: 4.4%
- From 2.5 to 3: 1.7%
- Beyond 3: 0.1%

**Calculation Steps:**

1. Convert ages 22 and 57 to z-scores:
   \[
   z = \frac{(X - \text{mean})}{\text{standard deviation}}
   \]
   For 22:
   \[
   z = \frac{(22 - 43)}{14} = -1.5
   \]
   For 57:
   \[
   z = \frac{(57 - 43)}{14} = 1
   \]

2. Use these z-scores to identify the area under the curve.
   - From z = -1.5 to z = 1:
     - -1.5 to 0: 9.2% + 15.0% = 24.2%
     - 0 to 1: 19.1%
Transcribed Image Text:**Problem Statement:** The ages of the population of a town are normally distributed with a mean of 43 and a standard deviation of 14. The town has a population of 5,000. How many would you expect to be aged between 22 and 57? **Solution Approach:** To solve this, use the provided Standard Normal Distribution curve. **Graph Explanation:** The graph is a bell-shaped curve, typical of a standard normal distribution, with the mean at the center (0) and standard deviations marked along the x-axis from -3 to 3. The percentages in the graph represent the proportion of the population within each segment: - From -3 to -2.5: 0.1% - From -2.5 to -2: 0.5% - From -2 to -1.5: 1.7% - From -1.5 to -1: 4.4% - From -1 to -0.5: 9.2% - From -0.5 to 0: 15.0% - From 0 to 0.5: 19.1% - From 0.5 to 1: 19.1% - From 1 to 1.5: 15.0% - From 1.5 to 2: 9.2% - From 2 to 2.5: 4.4% - From 2.5 to 3: 1.7% - Beyond 3: 0.1% **Calculation Steps:** 1. Convert ages 22 and 57 to z-scores: \[ z = \frac{(X - \text{mean})}{\text{standard deviation}} \] For 22: \[ z = \frac{(22 - 43)}{14} = -1.5 \] For 57: \[ z = \frac{(57 - 43)}{14} = 1 \] 2. Use these z-scores to identify the area under the curve. - From z = -1.5 to z = 1: - -1.5 to 0: 9.2% + 15.0% = 24.2% - 0 to 1: 19.1%
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