10. Result: Proof. Evaluate the proposed incorrect proof of the following result. That is, explain what is incorrect. If m is an even integer and n is an odd integer, then 3m + 5n is odd. We assume that m is an even integer and n is an odd integer. Then m = 2k and n = 2k+1, where k is an integer. Therefore, = 3(2k) + 5(2k+1) = 6k + 10k + 5 = 16k + 5 = = 2(8k+2) + 1 Since 8k+2 is an integer, 3m+5n is odd. Q.E.D. 3m + 5n

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ISBN:9780470458365
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Writing and Proof:

 

10.
Evaluate the proposed incorrect proof of the following result
That is, explain what is incorrect.
Result:
If m is an even integer and n is an odd integer, then 3m + 5n
is odd.
We assume that m is an even integer and n is an odd integer.
Then m = 2k and n =
Proof.
2k+1, where k is an integer. Therefore
= 3(2k) + 5(2k+1)
= 6k + 10k + 5
= 16k + 5
= 2(8k+2) + 1
Зт + 5п
Since 8k+2 is an integer, 3m+5n is odd. Q.E.D.
Transcribed Image Text:10. Evaluate the proposed incorrect proof of the following result That is, explain what is incorrect. Result: If m is an even integer and n is an odd integer, then 3m + 5n is odd. We assume that m is an even integer and n is an odd integer. Then m = 2k and n = Proof. 2k+1, where k is an integer. Therefore = 3(2k) + 5(2k+1) = 6k + 10k + 5 = 16k + 5 = 2(8k+2) + 1 Зт + 5п Since 8k+2 is an integer, 3m+5n is odd. Q.E.D.
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