10. Reginald wants to buy a new collar for each of his 3 dogs. The collars come in a choice of 7 different colors. Step 1. How many selections of collars for the 3 dogs are possible if repetitions of colors are allowed? Answer: Step 2. How many selections of collars are possible if repetitions of colors are not allowed? nswer:

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
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Chapter9: Sequences, Probability And Counting Theory
Section9.5: Counting Principles
Problem 40SE: A family consisting of 2 parents and 3 children is to pose for a picture with 2 family members in...
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### Educational Resources on Combinatorics and Probability

#### Problem 18
**Question:** A value meal package at Ron's Subs consists of a drink, a sandwich, and a bag of chips. There are 5 types of drinks to choose from, 5 types of sandwiches, and 3 types of chips. How many different value meal packages are possible?

**Answer:** 75

*Explanation:* The number of different value meal combinations can be calculated by multiplying the number of choices for each component:  
\[ \text{Total packs} = 5 \, (\text{drinks}) \times 5 \, (\text{sandwiches}) \times 3 \, (\text{chips}) = 75 \]

#### Problem 19
**Question:** Evaluate the following expression: \( 12! \)

**Answer:** 479,001,600

*Explanation:* The notation \( 12! \) represents the factorial of 12, which is the product of all positive integers up to 12:
\[ 12! = 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 479,001,600 \]

#### Problem 20
**Question:** Reginald wants to buy a new collar for each of his 3 dogs. The collars come in a choice of 7 different colors.

**Step 1:** How many selections of collars for the 3 dogs are possible if repetitions of colors are allowed?

**Answer:** ____

*Explanation:* Assuming each dog can have any of the 7 different colors, and the same color can be used more than once, the number of possible combinations is:  
\[ 7 \, (\text{colors for Dog 1}) \times 7 \, (\text{colors for Dog 2}) \times 7 \, (\text{colors for Dog 3}) = 7^3 = 343 \]

**Step 2:** How many selections of collars are possible if repetitions of colors are not allowed?

**Answer:** ____

*Explanation:* If each dog must have a different collar color, the number of possible selections can be calculated using permutations:  
\[ 7 \, (\text{choices for Dog 1}) \times 6 \, (\text{choices
Transcribed Image Text:### Educational Resources on Combinatorics and Probability #### Problem 18 **Question:** A value meal package at Ron's Subs consists of a drink, a sandwich, and a bag of chips. There are 5 types of drinks to choose from, 5 types of sandwiches, and 3 types of chips. How many different value meal packages are possible? **Answer:** 75 *Explanation:* The number of different value meal combinations can be calculated by multiplying the number of choices for each component: \[ \text{Total packs} = 5 \, (\text{drinks}) \times 5 \, (\text{sandwiches}) \times 3 \, (\text{chips}) = 75 \] #### Problem 19 **Question:** Evaluate the following expression: \( 12! \) **Answer:** 479,001,600 *Explanation:* The notation \( 12! \) represents the factorial of 12, which is the product of all positive integers up to 12: \[ 12! = 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 479,001,600 \] #### Problem 20 **Question:** Reginald wants to buy a new collar for each of his 3 dogs. The collars come in a choice of 7 different colors. **Step 1:** How many selections of collars for the 3 dogs are possible if repetitions of colors are allowed? **Answer:** ____ *Explanation:* Assuming each dog can have any of the 7 different colors, and the same color can be used more than once, the number of possible combinations is: \[ 7 \, (\text{colors for Dog 1}) \times 7 \, (\text{colors for Dog 2}) \times 7 \, (\text{colors for Dog 3}) = 7^3 = 343 \] **Step 2:** How many selections of collars are possible if repetitions of colors are not allowed? **Answer:** ____ *Explanation:* If each dog must have a different collar color, the number of possible selections can be calculated using permutations: \[ 7 \, (\text{choices for Dog 1}) \times 6 \, (\text{choices
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