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(10). For pacemaker batteries using the this chemistry (2Li + 12- 2Lil) to discharge, you would expect the positive electrode to be: A. Li electrode B. I2 electrode C. No electrode needed D. Either sidel

(10). For pacemaker batteries using the this chemistry (2Li + 12- 2Lil) to discharge, you would expect the positive electrode to be: A. Li electrode B. I2 electrode C. No electrode needed D. Either sidel

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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**Question 10:** In the context of pacemaker batteries using the chemical reaction \(2\text{Li} + \text{I}_2 \rightarrow 2\text{LiI}\) to discharge, identify the positive electrode. **Options:** A. Li electrode B. I\(_2\) electrode C. No electrode needed D. Either side **Explanation:** The given chemical equation represents the reaction in lithium-iodine batteries, commonly used in pacemakers. The positive electrode in such batteries is typically the iodine (\(I_2\)) electrode, as iodine is reduced during the reaction, accepting electrons and forming lithium iodide (\(LiI\)). Therefore, the correct answer is B. I\(_2\) electrode.
Transcribed Image Text:**Question 10:** In the context of pacemaker batteries using the chemical reaction \(2\text{Li} + \text{I}_2 \rightarrow 2\text{LiI}\) to discharge, identify the positive electrode. **Options:** A. Li electrode B. I\(_2\) electrode C. No electrode needed D. Either side **Explanation:** The given chemical equation represents the reaction in lithium-iodine batteries, commonly used in pacemakers. The positive electrode in such batteries is typically the iodine (\(I_2\)) electrode, as iodine is reduced during the reaction, accepting electrons and forming lithium iodide (\(LiI\)). Therefore, the correct answer is B. I\(_2\) electrode.
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