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10. Calculate the equilibrium potential for the reaction Az₂O + 2H* + 2e = 2Az +H₂O at pH = 12. (a) 0.271 V (b) 0.631 V (c) 0.751 V (d) 0.321 V 11. Calculate the equilibrium potential for reaction for the reaction, Az* +e = Az for [Az*] = 10-6 M. (a) 0.340 V (b) 0.370 V (c) 0.770 V (d) 0.140 V

10. Calculate the equilibrium potential for the reaction Az₂O + 2H* + 2e = 2Az +H₂O at pH = 12. (a) 0.271 V (b) 0.631 V (c) 0.751 V (d) 0.321 V 11. Calculate the equilibrium potential for reaction for the reaction, Az* +e = Az for [Az*] = 10-6 M. (a) 0.340 V (b) 0.370 V (c) 0.770 V (d) 0.140 V

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please solve 11 and 10
Problems 6-11 Arizonium (Az) is a newly discovered element. Below is a Table listing the chemical potentials at 300 K of the A* cation and the Az₂O oxide. Dissolved substances Az* H+ Solid substances Az Az₂O Liquid substances H₂O μº chemical potential (Joule/mole) 48,250 0 6. Determine the standard potential (Az* = 1M) for the reaction: Az* +e* = Az (a) 0.400 V. (b) 0.500 V (c) 0.700 V (d) 0.800 V 7. Determine the standard potential for the reaction: Az₂O + 2H+ +2e= 2Az +H₂O (a) 0.991 V (b) 0.701 V (c) 0.698 V (d) 1.203 V 8. Calculate the equilibrium constant, K, for the chemical reaction:2Az* + H₂O=Az₂O + 2H* (a) 10-11.3 (b) 10-10.1 (c) 10-6.0 (d) 10-16.4 (a) 5.5 Dashboard 0 -45953 9. Determine the pH value at which the potential for the two reactions, Azt +e= Az and Az₂O + 2H+ + 2e = 2Az +H₂O, intersect. (b) 6.2 -237,191 000 logo Calendar (d) 10.1 10. Calculate the equilibrium potential for the reaction Az₂O + 2H+ + 2e = 2Az +H₂O at pH = 12. (a) 0.271 V (b) 0.631 V (d) 0.321 V 11. Calculate the equilibrium potential for reaction for the reaction, Az+ +e* = Az for [Az*] = 106 M. (a) 0.340 V (b) 0.370 V (c) 8.2 (c) 0.751 V (c) 0.770 V (d) 0.140 V 5 To Do Notifications 31 Inbox
Transcribed Image Text:Problems 6-11 Arizonium (Az) is a newly discovered element. Below is a Table listing the chemical potentials at 300 K of the A* cation and the Az₂O oxide. Dissolved substances Az* H+ Solid substances Az Az₂O Liquid substances H₂O μº chemical potential (Joule/mole) 48,250 0 6. Determine the standard potential (Az* = 1M) for the reaction: Az* +e* = Az (a) 0.400 V. (b) 0.500 V (c) 0.700 V (d) 0.800 V 7. Determine the standard potential for the reaction: Az₂O + 2H+ +2e= 2Az +H₂O (a) 0.991 V (b) 0.701 V (c) 0.698 V (d) 1.203 V 8. Calculate the equilibrium constant, K, for the chemical reaction:2Az* + H₂O=Az₂O + 2H* (a) 10-11.3 (b) 10-10.1 (c) 10-6.0 (d) 10-16.4 (a) 5.5 Dashboard 0 -45953 9. Determine the pH value at which the potential for the two reactions, Azt +e= Az and Az₂O + 2H+ + 2e = 2Az +H₂O, intersect. (b) 6.2 -237,191 000 logo Calendar (d) 10.1 10. Calculate the equilibrium potential for the reaction Az₂O + 2H+ + 2e = 2Az +H₂O at pH = 12. (a) 0.271 V (b) 0.631 V (d) 0.321 V 11. Calculate the equilibrium potential for reaction for the reaction, Az+ +e* = Az for [Az*] = 106 M. (a) 0.340 V (b) 0.370 V (c) 8.2 (c) 0.751 V (c) 0.770 V (d) 0.140 V 5 To Do Notifications 31 Inbox
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Ques 10: Equilibrium potential of bold italic A bold italic z subscript bold 2 bold O bold plus bold 2 bold H to the power of bold plus bold plus bold 2 bold e to the power of bold minus bold equals bold 2 bold italic A bold italic z bold space bold plus bold space bold H subscript bold 2 bold O

Ques 11: Equilibrium potential of  bold Az to the power of bold plus bold plus bold e to the power of bold minus bold equals bold Az

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