HELP! I am new to this so can you please provide an explanation on what this means and show the answer by plugging in the numbers while solving It would help a lot! Thank you! 10. An artist must push with a minimum force of 75 N at an angle of 45° to a picture to hold itin equilibrium. The coefficient of friction between the wall and the picture frame is 0.30.What is the mass of the picture?Σ Fx = FN - Fx = 0F= 75NFx = FN = 75 cos 45 = 53.0NΣ Fy = Fy + F₂ - 5 = 0Fg = Fy + Ff = Fy + M FNA.1.6 kgB.2.3 kgC.3.8 kgD7.0 kg== 75 sin 45+ (0.30) (53.0)68.9Nm=gFx==7.0kyFfF=75 NFN101 1

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Answered: 10. An artist must push with a minimum…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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HELP! I am new to this so can you please provide an explanation on what this means and show the answer by plugging in the numbers while solving It would help a lot! Thank you!

10. An artist must push with a minimum force of 75 N at an angle of 45° to a picture to hold it
in equilibrium. The coefficient of friction between the wall and the picture frame is 0.30.
What is the mass of the picture?
Σ Fx = FN - Fx = 0
F= 75N
Fx = FN = 75 cos 45 = 53.0N
Σ Fy = Fy + F₂ - 5 = 0
Fg = Fy + Ff = Fy + M FN
A.
1.6 kg
B.
2.3 kg
C.
3.8 kg
D
7.0 kg
=
= 75 sin 45+ (0.30) (53.0)
68.9N
m=
g
Fx
=
=
7.0ky
Ff
F=75 N
FN
101 1

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