Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0 +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av

10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0 +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av

icon
Related questions
Question

The question is in the image I submitted 

10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0<x<+L/2 x > +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av
Transcribed Image Text:10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0<x<+L/2 x > +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer