10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0 +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av
10. A particle is represented by the following wave function: x < -L/2 -L/2 < x < 0 = C(-2x/L+1) 0 +L/2 Y (x) = 0 = C(2x/L+1) =D0 (a) Use the normalization condition to find C. (b) Eval- uate the probability to find the particle in an interval of width 0.010L at x = L/4 (that is, between x = 0.245L and x=0.255L. (No integral is necessary for this calculation.) (c) Evaluate the probability to find the particle between x = 0 and x = the rms value of x: xms = V(x²),- %3D %3D %3D +L]4. (d) Find the average value of x and %3D av
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![10. A particle is represented by the following wave function:
x < -L/2
-L/2 < x < 0
= C(-2x/L+1) 0<x<+L/2
x > +L/2
Y (x) = 0
= C(2x/L+1)
=D0
(a) Use the normalization condition to find C. (b) Eval-
uate the probability to find the particle in an interval of
width 0.010L at x = L/4 (that is, between x = 0.245L and
x=0.255L. (No integral is necessary for this calculation.)
(c) Evaluate the probability to find the particle between
x = 0 and x =
the rms value of x: xms = V(x²),-
%3D
%3D
%3D
+L]4. (d) Find the average value of x and
%3D
av](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F198c2fb2-d9a4-4cd3-9b0a-c435deff77bb%2F66e9e67b-4e24-4f3d-a8fe-7645eeb1bddf%2Fmo0y47o.jpeg&w=3840&q=75)
Transcribed Image Text:10. A particle is represented by the following wave function:
x < -L/2
-L/2 < x < 0
= C(-2x/L+1) 0<x<+L/2
x > +L/2
Y (x) = 0
= C(2x/L+1)
=D0
(a) Use the normalization condition to find C. (b) Eval-
uate the probability to find the particle in an interval of
width 0.010L at x = L/4 (that is, between x = 0.245L and
x=0.255L. (No integral is necessary for this calculation.)
(c) Evaluate the probability to find the particle between
x = 0 and x =
the rms value of x: xms = V(x²),-
%3D
%3D
%3D
+L]4. (d) Find the average value of x and
%3D
av
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