10. A comet with a hyperbolic orbit passes within 572,000 miles of the center of the sun with the sun as a focus of its orbit. Find an equation for the path of the comet using (572,000, 0) as the vertex and (429,000, 436,500) as another point in the comet's path. (x-1,144,000)² [A] 572,0002 =1; 582,000- xs572,000 (x-572,000)² [B] 429,000 =1; 436,500 xs572,000 [C] 429,000? (v-1,144,000)² _ ,. 436,500 =13; xs572,000 [D] 572,000? (y-572,000)² 582,000 =1;
10. A comet with a hyperbolic orbit passes within 572,000 miles of the center of the sun with the sun as a focus of its orbit. Find an equation for the path of the comet using (572,000, 0) as the vertex and (429,000, 436,500) as another point in the comet's path. (x-1,144,000)² [A] 572,0002 =1; 582,000- xs572,000 (x-572,000)² [B] 429,000 =1; 436,500 xs572,000 [C] 429,000? (v-1,144,000)² _ ,. 436,500 =13; xs572,000 [D] 572,000? (y-572,000)² 582,000 =1;
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![10. A comet with a hyperbolic orbit passes
within 572,000 miles of the center of the sun
with the sun as a focus of its orbit. Find an
equation for the path of the comet
using (572,000, 0) as the vertex and
(429,000, 436,500) as another point in the
comet's path.
(x-1,144,000)
[A]
572,000?
=13B
582,000
x<572,000
(x-572,000)
[B]
429,000?
=1;
436,500?
x<572,000
[C]
429,000?
(y-1,144,000)
=1;
436,500?
x<572,000
(y – 572,000)
=1;
[D]
572,000
582,000?
x<572,000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38f04fa2-35f5-4e54-95e1-8265f4192f51%2F6bfff6bd-8218-4b86-bb8a-8354055273d5%2Ff1k0ilm_processed.png&w=3840&q=75)
Transcribed Image Text:10. A comet with a hyperbolic orbit passes
within 572,000 miles of the center of the sun
with the sun as a focus of its orbit. Find an
equation for the path of the comet
using (572,000, 0) as the vertex and
(429,000, 436,500) as another point in the
comet's path.
(x-1,144,000)
[A]
572,000?
=13B
582,000
x<572,000
(x-572,000)
[B]
429,000?
=1;
436,500?
x<572,000
[C]
429,000?
(y-1,144,000)
=1;
436,500?
x<572,000
(y – 572,000)
=1;
[D]
572,000
582,000?
x<572,000
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