10. A cannonball is shot out of a cannon buried 2 m in the ground. The height of the cannonball can be approximated by the equation h(t) is the height of the ball, in metres, and t is the time, in seconds. -512 + 35t- 2, where h(t)
10. A cannonball is shot out of a cannon buried 2 m in the ground. The height of the cannonball can be approximated by the equation h(t) is the height of the ball, in metres, and t is the time, in seconds. -512 + 35t- 2, where h(t)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:10. A cannonball is shot out of a cannon
buried 2 m in the ground. The height of
the cannonball can be approximated by the
equation h(t) = -512 + 35t - 2, where h(t)
is the height of the ball, in metres, and t is
the time, in seconds.
a) How long will it take the cannonball to
reach ground level, to the nearest tenth
of a second?
b) How long is the cannonball in the air, to
the nearest tenth of a second?
c) Find the maximum height of the
cannonball and the time it takes to reach
this height.
d) Sketch a graph of the path of the
cannonball. Label key features.
e) Determine the time intervalş for which
the cannonball is increasing and
decreasing in height.
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