Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The image presents a mathematical problem involving integration with a graph for visual reference. The problem is as follows:
What is the value of \( \int_{4}^{10} F'(x) \, dx \)?
The graph displayed is a plot of the function \( F(x) \) with \( x \) along the horizontal axis and \( F(x) \) along the vertical axis. It is laid on a grid with increments marked.
- The graph shows an increasing curve starting at approximately \( F(1) = 9 \) and reaching a peak at around \( x = 8 \) with \( F(8) = 22 \).
- The curve then slightly declines, showing \( F(10) = 18 \).
This setup suggests that the integral of the derivative \( F'(x) \) over the interval from 4 to 10 can be understood as the net change in \( F(x) \) between these points. Given the values:
- \( F(10) = 18 \)
- \( F(4) = 12 \)
The value of the integral \( \int_{4}^{10} F'(x) \, dx \) would be the change in \( F(x) \) over this interval, calculated as:
\[
F(10) - F(4) = 18 - 12 = 6
\]
Therefore, the value of the integral is 6.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72b83cc2-495e-4bc5-a028-f79dc88fc308%2F19994e14-7bcb-48ac-a72a-a6806e42ed0a%2Fwohq6tfg_processed.png&w=3840&q=75)
Transcribed Image Text:The image presents a mathematical problem involving integration with a graph for visual reference. The problem is as follows:
What is the value of \( \int_{4}^{10} F'(x) \, dx \)?
The graph displayed is a plot of the function \( F(x) \) with \( x \) along the horizontal axis and \( F(x) \) along the vertical axis. It is laid on a grid with increments marked.
- The graph shows an increasing curve starting at approximately \( F(1) = 9 \) and reaching a peak at around \( x = 8 \) with \( F(8) = 22 \).
- The curve then slightly declines, showing \( F(10) = 18 \).
This setup suggests that the integral of the derivative \( F'(x) \) over the interval from 4 to 10 can be understood as the net change in \( F(x) \) between these points. Given the values:
- \( F(10) = 18 \)
- \( F(4) = 12 \)
The value of the integral \( \int_{4}^{10} F'(x) \, dx \) would be the change in \( F(x) \) over this interval, calculated as:
\[
F(10) - F(4) = 18 - 12 = 6
\]
Therefore, the value of the integral is 6.
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