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+10 V 1.0 kQ V out Vin oV -10 V

+10 V 1.0 kQ V out Vin oV -10 V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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If the diode is ideal, then fine out the output waveform. 

This image depicts an electronic circuit diagram for a half-wave rectifier. Here's a detailed explanation: **Components and Symbols:** - **Diode:** Positioned in the middle of the circuit, allows current to pass in one direction. - **Resistor:** A 1.0 kΩ resistor is connected in series with the diode. - **Ground:** The symbol at the bottom represents the ground connection. - **Voltage Source (Vin):** Depicted by a sinusoidal waveform on the left, with peak values at +10 V, 0 V, and -10 V. **Circuit Description:** - The **input voltage (Vin)** is an AC signal that oscillates between +10 V and -10 V. - As the AC voltage enters the circuit, the **diode** only allows the positive half of the AC signal to pass through, blocking the negative half. - The current that passes through the diode then flows through the **resistor (1.0 kΩ)**. - The **output voltage (Vout)** is taken across the resistor, resulting in a pulsating DC voltage. This configuration is commonly used to convert AC signals into DC signals for power supplies, with applications across various electronics.
Transcribed Image Text:This image depicts an electronic circuit diagram for a half-wave rectifier. Here's a detailed explanation: **Components and Symbols:** - **Diode:** Positioned in the middle of the circuit, allows current to pass in one direction. - **Resistor:** A 1.0 kΩ resistor is connected in series with the diode. - **Ground:** The symbol at the bottom represents the ground connection. - **Voltage Source (Vin):** Depicted by a sinusoidal waveform on the left, with peak values at +10 V, 0 V, and -10 V. **Circuit Description:** - The **input voltage (Vin)** is an AC signal that oscillates between +10 V and -10 V. - As the AC voltage enters the circuit, the **diode** only allows the positive half of the AC signal to pass through, blocking the negative half. - The current that passes through the diode then flows through the **resistor (1.0 kΩ)**. - The **output voltage (Vout)** is taken across the resistor, resulting in a pulsating DC voltage. This configuration is commonly used to convert AC signals into DC signals for power supplies, with applications across various electronics.
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