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10) s(t) = 1² – 5t – 24; 0sts 8

10) s(t) = 1² – 5t – 24; 0sts 8

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the distance traveled for Number 10) ONLY
A particle moves along a horizontal line. Its position function is s(t) for t 0. For each problem, find the displacement of the particle and the distance traveled by the particle over the given interval. UCU= 2C1)-18 =2-18=-1 = 2-16= -14 VCA)こ1C)ー( 7) slt) = 1² – 181+ 65; 7sts 11 VCiO) = 2C10)-18 20-18= 2 8) s(t) = t² – 161 + 64; 5 sts 12 K CI)-X(7)= O UCt)-2セー18 UCE)= 2t-16 XC12)- XC5) =O s(12)=12)-16(1z) t64 = 144-192464=16 2t-18=0 Zt-16= 0 2(tー8)=0 t-6=0 = 121 -198+65=-12 2(t-9)=0 t-9=0 もニ9 = 25- 80+64=9 16-9= 7 49-12646512 7=0 -12+12=0 O =0 t=8 Moves leet from testo t8 Moves nght from t-8to t=12 = 64-128+64 t=9 Moves left from t=7t0 この Moves right from t9 tot=| 81-162 t65=-16 IXca)- xC7)+ Ixc) -16+12 E O-9 + 16-0 -12 +16 Displacoment: o Distance fraveled 8 = 141+141 = |-91 t ll61 4 +4=8 E9 t16 =25 Displacement:7 -2- Distance traveled: 25 VC)-2Cー2 E 2-21 -19 VC3)= ZC3)-S VC2)こZC2)-ら E4-5- 9) s(t) = 1² – 21t + 90; 4 sts 15 10) s(t) = t² – 5t – 24; 0sts 8 = 22 -21
Transcribed Image Text:A particle moves along a horizontal line. Its position function is s(t) for t 0. For each problem, find the displacement of the particle and the distance traveled by the particle over the given interval. UCU= 2C1)-18 =2-18=-1 = 2-16= -14 VCA)こ1C)ー( 7) slt) = 1² – 181+ 65; 7sts 11 VCiO) = 2C10)-18 20-18= 2 8) s(t) = t² – 161 + 64; 5 sts 12 K CI)-X(7)= O UCt)-2セー18 UCE)= 2t-16 XC12)- XC5) =O s(12)=12)-16(1z) t64 = 144-192464=16 2t-18=0 Zt-16= 0 2(tー8)=0 t-6=0 = 121 -198+65=-12 2(t-9)=0 t-9=0 もニ9 = 25- 80+64=9 16-9= 7 49-12646512 7=0 -12+12=0 O =0 t=8 Moves leet from testo t8 Moves nght from t-8to t=12 = 64-128+64 t=9 Moves left from t=7t0 この Moves right from t9 tot=| 81-162 t65=-16 IXca)- xC7)+ Ixc) -16+12 E O-9 + 16-0 -12 +16 Displacoment: o Distance fraveled 8 = 141+141 = |-91 t ll61 4 +4=8 E9 t16 =25 Displacement:7 -2- Distance traveled: 25 VC)-2Cー2 E 2-21 -19 VC3)= ZC3)-S VC2)こZC2)-ら E4-5- 9) s(t) = 1² – 21t + 90; 4 sts 15 10) s(t) = t² – 5t – 24; 0sts 8 = 22 -21
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