10 points What element should go in the empty box in this equation? As→ B+O 33 79 se 79 Ge 34 32 Option 2 O Option 1 83 75 Ga 31 Br 35 O Answer Option 3

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Chapter1: Chemical Foundations
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**Transcription:**

**Title:** Beta Decay Equation

**Question:** What element should go in the empty box in this equation?

**Equation:**

\[ \text{As}^{79}_{33} \rightarrow \boxplus + ^0_{-1}\beta \]

**Options:**

- Option 1: \(\text{Se}^{79}_{34}\) 
- Option 2: \(\text{Ge}^{79}_{32}\)
- Option 3: \(\text{Ga}^{75}_{31}\)
- Answer: \(\text{Br}^{83}_{35}\)

**Explanation of Diagram:**

The image shows a nuclear equation representing a beta decay process. In the equation, arsenic (As) undergoes beta decay, emitting a beta particle (\(^0_{-1}\beta\)) and transforming into another element. The user is tasked with identifying the product of this decay from a selection of possible elements with their respective atomic numbers and mass numbers.

**Key Points:**

- The starting element is Arsenic (\(\text{As}\)) with a mass number of 79 and an atomic number of 33.
- In beta decay, a neutron is converted into a proton, thereby increasing the atomic number by 1 while the mass number remains unchanged.
- The goal is to find the element that results when one proton is added to Arsenic, resulting in the transformation into Selenium (\(\text{Se}\)) with atomic number 34.

**Correct Answer:** \(\text{Se}^{79}_{34}\)
Transcribed Image Text:**Transcription:** **Title:** Beta Decay Equation **Question:** What element should go in the empty box in this equation? **Equation:** \[ \text{As}^{79}_{33} \rightarrow \boxplus + ^0_{-1}\beta \] **Options:** - Option 1: \(\text{Se}^{79}_{34}\) - Option 2: \(\text{Ge}^{79}_{32}\) - Option 3: \(\text{Ga}^{75}_{31}\) - Answer: \(\text{Br}^{83}_{35}\) **Explanation of Diagram:** The image shows a nuclear equation representing a beta decay process. In the equation, arsenic (As) undergoes beta decay, emitting a beta particle (\(^0_{-1}\beta\)) and transforming into another element. The user is tasked with identifying the product of this decay from a selection of possible elements with their respective atomic numbers and mass numbers. **Key Points:** - The starting element is Arsenic (\(\text{As}\)) with a mass number of 79 and an atomic number of 33. - In beta decay, a neutron is converted into a proton, thereby increasing the atomic number by 1 while the mass number remains unchanged. - The goal is to find the element that results when one proton is added to Arsenic, resulting in the transformation into Selenium (\(\text{Se}\)) with atomic number 34. **Correct Answer:** \(\text{Se}^{79}_{34}\)
Expert Solution
Step 1

Beta decay is a process in which one neutron converts into a proton. 

The parent element and daughter elements after one beta emission will have same mass no. Hence, they become isobar. 

But, atomic no. of daughter element is increased by one unit. 

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