10) P (-2, 0), Q (10, -14), and R (-4, -2), then determine the distance between each point. Th state whether PQ = QR. • is congruent by stating yes or no.

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter11: Conics
Section11.1: Distance And Midpoint Formulas; Circles
Problem 11.7TI: Use the Midpoint Formula to find the midpoint of the line segments whose endpoints are (3,5) and...
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**Problem 10)** Given points P (-2, 0), Q (10, -14), and R (-4, -2), first determine the distance between each pair of points. Then state whether line segment \( \overline{PQ} \cong \overline{QR} \) is congruent by stating yes or no.

To determine the distances, we use the distance formula: 

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

**Step 1:** Calculate the distance \( \overline{PQ} \).

P (-2, 0) and Q (10, -14)

\[ d_{PQ} = \sqrt{(10 - (-2))^2 + (-14 - 0)^2} \]
\[ d_{PQ} = \sqrt{(10 + 2)^2 + (-14)^2} \]
\[ d_{PQ} = \sqrt{12^2 + (-14)^2} \]
\[ d_{PQ} = \sqrt{144 + 196} \]
\[ d_{PQ} = \sqrt{340} \]
\[ d_{PQ} = \sqrt{4 * 85} \]
\[ d_{PQ} = 2\sqrt{85} \]

**Step 2:** Calculate the distance \( \overline{QR} \).

Q (10, -14) and R (-4, -2)

\[ d_{QR} = \sqrt{(-4 - 10)^2 + (-2 - (-14))^2} \]
\[ d_{QR} = \sqrt{(-4 - 10)^2 + (-2 + 14)^2} \]
\[ d_{QR} = \sqrt{(-14)^2 + 12^2} \]
\[ d_{QR} = \sqrt{196 + 144} \]
\[ d_{QR} = \sqrt{340} \]
\[ d_{QR} = \sqrt{4 * 85} \]
\[ d_{QR} = 2\sqrt{85} \]

**Conclusion:**

Since \( d_{PQ} = d_{QR} = 2\sqrt{85} \), it is clear that \( \overline{PQ} \) is congruent to \( \overline{QR} \).

**Answer:**
Transcribed Image Text:**Problem 10)** Given points P (-2, 0), Q (10, -14), and R (-4, -2), first determine the distance between each pair of points. Then state whether line segment \( \overline{PQ} \cong \overline{QR} \) is congruent by stating yes or no. To determine the distances, we use the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] **Step 1:** Calculate the distance \( \overline{PQ} \). P (-2, 0) and Q (10, -14) \[ d_{PQ} = \sqrt{(10 - (-2))^2 + (-14 - 0)^2} \] \[ d_{PQ} = \sqrt{(10 + 2)^2 + (-14)^2} \] \[ d_{PQ} = \sqrt{12^2 + (-14)^2} \] \[ d_{PQ} = \sqrt{144 + 196} \] \[ d_{PQ} = \sqrt{340} \] \[ d_{PQ} = \sqrt{4 * 85} \] \[ d_{PQ} = 2\sqrt{85} \] **Step 2:** Calculate the distance \( \overline{QR} \). Q (10, -14) and R (-4, -2) \[ d_{QR} = \sqrt{(-4 - 10)^2 + (-2 - (-14))^2} \] \[ d_{QR} = \sqrt{(-4 - 10)^2 + (-2 + 14)^2} \] \[ d_{QR} = \sqrt{(-14)^2 + 12^2} \] \[ d_{QR} = \sqrt{196 + 144} \] \[ d_{QR} = \sqrt{340} \] \[ d_{QR} = \sqrt{4 * 85} \] \[ d_{QR} = 2\sqrt{85} \] **Conclusion:** Since \( d_{PQ} = d_{QR} = 2\sqrt{85} \), it is clear that \( \overline{PQ} \) is congruent to \( \overline{QR} \). **Answer:**
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