10 KN8 KN6 ΚΝDesign the beam ifallowable shear stress of thebeam is 1.80 MPa andallowable flexural stress is32 MPа.5 KN/mACAssume that b = 150 mmand neglect the weight ofthe beam%3D2.002.001.00in meters

Let the reaction force at A and D be RA and RD . From force balance - RA+RD =10+8+6+5×5=49 kNTaking…

Answered: 10 KN 8 ΚΝ 6 KN Design the beam if…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The beam supports the triangular distributed load shown below with Wmax = 900 lb/ft. The reactions at A and B are vertical. (Figure 1) Figure AT PORCE 6 ft D 6 ft C 6 ft W IB TODAY E 4.5 ft 4.5 ft Part A Determine the magnitude of the resultant internal normal force on the cross section at point D. Express your answer in kilopounds to three significant figures. ND= Submit Part B Vp= Submit Part C ΠΙΑΣΦΗΜ Mp= Avec Submit Request Answer Determine the magnitude of the resultant internal shear force on the cross section at point D. Express your answer in kilopounds to three significant figures. ΠΙΑΣΦΩΤ Request Answer n Request Answer vec 1 → C vec S S ? Determine the magnitude of the resultant internal bending moment on the cross section at point D. Express your answer in kilopound-feet to three significant figures. [Γ]ΑΣΦ [4 O I ? kip ? kip kip.ft
What is the maximum length of a uniformly loaded, simply supported beam based on the maximum allowable stresses, its normal stress of 90MPa and its shear stress of 100MPa? The uniform load is 10kN/m. The area is b = 20mm and h = 80mm
481 A Find the shear force and bending moment at points C and D. 300 lb/ft Answer: Vc = -2.11 kip Mc = -3.72 kip ft VD = 900 lbf Mp = -7.35 kip ft D 12 ft 15 ft C weights Lea... B D 3 ft 6 ft I Centroids -... 6000 lb-ft G4.4.1 Weight...
a) A steel 4 X 4X 0.25-inch square tube (moment of inertia I = 8.215 inª) is used as a simply supported beam. A 100-pound weight is dropped from a height of 24 inches onto the beam at mid- span. Find the maximum stress in the beam. Use E = 29 X 106 psi. 8 ft k = 200 lb/in 100 lb 8 ft b) Instead of fixed supports, the beam is supported by springs at both ends. Find the maximum stress in the beam when the 100-pound weight is dropped from a height of 24 inches (same beam properties as in part a). 24 in 100 lb 8 ft 24 in 8 ft k = 200 lb/in
Calculate reactions Ra and Rb with the following values F1 = 230 F2 = 582 Udl = 2000N with workings out please. Thanks.
For the beam shown below, calculate the minimum value of b considering that allowable normal stress and shear stress for the material used are 12 MPa and 825 kPa, respectively. 2.4 kN 4.8 kN B CY A D 150 mm

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10 KN 8 ΚΝ 6 KN Design the beam if allowable shear stress of the beam is 1.80 MPa and allowable flexural stress is 32 MPa. 5 KN/m A, C Assume thatb = 150 mm and neglect the weight of the beam 2.00 2.00 1.00 in meters