10 kN 20 kN 10 kN 15 kN E G F 3 4 6 m 8 m -4 m 4 m-4 m--4 m- (a) 10 20 10 E 15 15 25 15 0 7,07, 0. 10 20 10 25 15 B, = 20 7.07/ 20 B A, = 5- B, = 25 A = 15 (b) 20 15 3 4 FOF FCF (c) FIG. 4.21
10 kN 20 kN 10 kN 15 kN E G F 3 4 6 m 8 m -4 m 4 m-4 m--4 m- (a) 10 20 10 E 15 15 25 15 0 7,07, 0. 10 20 10 25 15 B, = 20 7.07/ 20 B A, = 5- B, = 25 A = 15 (b) 20 15 3 4 FOF FCF (c) FIG. 4.21
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Determine the force in each member of the three-hinged trussed arch shown in Fig. 4.21(a) by the method of joints

Transcribed Image Text:10 kN
20 kN
10 kN
15 kN E
G
F
3
4
6 m
8 m
-4 m
4 m-4 m--4 m-
(a)
10
20
10
E
15
15
25
15
0 7,07,
0.
10
20
10
25
15
B, = 20
7.07/
20
B
A, = 5-
B, = 25
A
= 15
(b)
20
15
3
4
FOF
FCF
(c)
FIG. 4.21
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