10 km/h at 30 degrees + 15 km/h 270 degrees The first picture is the steps. The second picture is an example of how to do. Correct me if I'm wrong.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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10 km/h at 30 degrees + 15 km/h 270 degrees

The first picture is the steps.

The second picture is an example of how to do. Correct me if I'm wrong.

## Vector Worksheet #3

**Scale:** 5 units = 1 cm  

### Problem 1:
Calculate the resultant vector from the following:

Vectors: 
- 10 km/h at 120° 
- 25 km/h at 180°

### Diagram:
- The diagram visually represents two vectors and their resultant. 
- Vector 1 is drawn at 120° from the reference line (horizontal eastward axis).
- Vector 2 is drawn at 180°, directly south along the Y axis.
- The resultant vector is shown in red, calculated from the addition of Vector 1 and Vector 2.

### Calculations:
1. **Resolve Vectors into Components**
   - \( V_{1x} = V_1 \cos(θ_1) = 10 \cos(120°) = 10(-0.5) = -5 \, \text{km/h} \)
   - \( V_{1y} = V_1 \sin(θ_1) = 10 \sin(120°) = 10(0.866) = 8.66 \, \text{km/h} \)
   - \( V_{2x} = V_2 \cos(θ_2) = 25 \cos(180°) = 25(-1) = -25 \, \text{km/h} \)
   - \( V_{2y} = V_2 \sin(180°) = 25 \sin(0) = 0 \, \text{km/h} \)

2. **Sum of Components**
   - \( V_x = V_{1x} + V_{2x} = (-5) + (-25) = -30 \, \text{km/h} \)
   - \( V_y = V_{1y} + V_{2y} = 8.66 + 0 = 8.66 \, \text{km/h} \)

3. **Magnitude of the Resultant Vector**
   - \( V_r = \sqrt{V_x^2 + V_y^2} = \sqrt{(-30)^2 + (8.66)^2} = \sqrt{900 + 75.0} = \sqrt{975} = 31.2 \, \text{km/h} \)

4. **Direction of the Resultant Vector**
   - \(
Transcribed Image Text:## Vector Worksheet #3 **Scale:** 5 units = 1 cm ### Problem 1: Calculate the resultant vector from the following: Vectors: - 10 km/h at 120° - 25 km/h at 180° ### Diagram: - The diagram visually represents two vectors and their resultant. - Vector 1 is drawn at 120° from the reference line (horizontal eastward axis). - Vector 2 is drawn at 180°, directly south along the Y axis. - The resultant vector is shown in red, calculated from the addition of Vector 1 and Vector 2. ### Calculations: 1. **Resolve Vectors into Components** - \( V_{1x} = V_1 \cos(θ_1) = 10 \cos(120°) = 10(-0.5) = -5 \, \text{km/h} \) - \( V_{1y} = V_1 \sin(θ_1) = 10 \sin(120°) = 10(0.866) = 8.66 \, \text{km/h} \) - \( V_{2x} = V_2 \cos(θ_2) = 25 \cos(180°) = 25(-1) = -25 \, \text{km/h} \) - \( V_{2y} = V_2 \sin(180°) = 25 \sin(0) = 0 \, \text{km/h} \) 2. **Sum of Components** - \( V_x = V_{1x} + V_{2x} = (-5) + (-25) = -30 \, \text{km/h} \) - \( V_y = V_{1y} + V_{2y} = 8.66 + 0 = 8.66 \, \text{km/h} \) 3. **Magnitude of the Resultant Vector** - \( V_r = \sqrt{V_x^2 + V_y^2} = \sqrt{(-30)^2 + (8.66)^2} = \sqrt{900 + 75.0} = \sqrt{975} = 31.2 \, \text{km/h} \) 4. **Direction of the Resultant Vector** - \(
**If you have two or more vectors and they are not on the x-y axis, you have to use both techniques:**

- **Use trig functions for each vector’s components:**

  \( D_y = D \sin \Theta \)

  \( D_x = D \cos \Theta \)

- **Solve for all x and y components.**

- **Find the sum (add) all x components, all y components.**

- **Use the Pythagorean theorem:**

  \( D = \sqrt{D_y^2 + D_x^2} \)

  - **Solve for theta:**

  \( \Theta = \tan^{-1} \frac{D_y}{D_x} \)
Transcribed Image Text:**If you have two or more vectors and they are not on the x-y axis, you have to use both techniques:** - **Use trig functions for each vector’s components:** \( D_y = D \sin \Theta \) \( D_x = D \cos \Theta \) - **Solve for all x and y components.** - **Find the sum (add) all x components, all y components.** - **Use the Pythagorean theorem:** \( D = \sqrt{D_y^2 + D_x^2} \) - **Solve for theta:** \( \Theta = \tan^{-1} \frac{D_y}{D_x} \)
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