Homework Help is Here – Start Your Trial Now!
Science
Chemistry
10) Calculate the following quantities: Vb Ma a) Volume (in ml) of 0.75 M HCl required to neutralized completely 25.0 ml of 0.15 M Ba(OH)2 HCL nap мь Ba(OH)2 nb= Mb= Vb= Ma= Va= namava-nbM6Vb b) if 30.0 ml of 0.75 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? c) Explain, how would you prepare 500.0 ml of 0.01 M NaOH solution starting with pure solid?

10) Calculate the following quantities: Vb Ma a) Volume (in ml) of 0.75 M HCl required to neutralized completely 25.0 ml of 0.15 M Ba(OH)2 HCL nap мь Ba(OH)2 nb= Mb= Vb= Ma= Va= namava-nbM6Vb b) if 30.0 ml of 0.75 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? c) Explain, how would you prepare 500.0 ml of 0.01 M NaOH solution starting with pure solid?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
icon
Concept explainers
Question
100%
I need help with question 10 a,b and c part
CHEM 1411/1311 Chapter 4 - Reactions in Aqueous Solutions 7) Using activity series table, what is the outcome of each of the following reactions? If no reaction occurs, simply write NR. a) Cu + Pb(NO3)2 → Cu(NO3) + Pb c) Br2 + NaCl → NaBr + Cl Cu + H₂O e) H₂ + CuO → 8) Calculate the following quantities: a) Molarity of a solution that contains 0. 05 mol Na2SO4 in 300 ml solution ń -0.05 moles M: VL M= VL: 300 TOOD = 0.301 0.301 b) Moles of HNO3 in 55.0 ml of 2.00 M solution of nitric acid n=M.VL VL= SS.OML 1000 L = 0.055L n M b) Mg + AgNO3 → Mg(NO3)2 + Ag d) Li + HCl LICI + Ha M-0.167 mole/L c) Volume (in ml) of 2.00 M Ca(OH)2 solution needed to supply 0.750 mol of Ca(OH)2 VL= VL= 0.750 mole 2.00 M NL= 0.375 L Mb= Vb= 9) Determine the concentration(molarity, M) of each ion present in the following solution: a) 0.25 M NaCl b) 0.25 M K2SO4 b) 0.25 M C6H12O6 Dr. Pahlavan n=(2.00m) (0.0SSL) → [n= 0.110 Mole HNO3) M7VL 10) Calculate the following quantities: Vb Ma мь a) Volume (in ml) of 0.75 M HCl required to neutralized completely 25.0 ml of 0.15 M Ba(OH)2 HCL Ba(OH)2 nap nb= Ma= Va= 2 namava-nbM6V6 b) if 30.0 ml of 0.75 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? c) Explain, how would you prepare 500.0 ml of 0.01 M NaOH solution starting with pure solid?
Transcribed Image Text:CHEM 1411/1311 Chapter 4 - Reactions in Aqueous Solutions 7) Using activity series table, what is the outcome of each of the following reactions? If no reaction occurs, simply write NR. a) Cu + Pb(NO3)2 → Cu(NO3) + Pb c) Br2 + NaCl → NaBr + Cl Cu + H₂O e) H₂ + CuO → 8) Calculate the following quantities: a) Molarity of a solution that contains 0. 05 mol Na2SO4 in 300 ml solution ń -0.05 moles M: VL M= VL: 300 TOOD = 0.301 0.301 b) Moles of HNO3 in 55.0 ml of 2.00 M solution of nitric acid n=M.VL VL= SS.OML 1000 L = 0.055L n M b) Mg + AgNO3 → Mg(NO3)2 + Ag d) Li + HCl LICI + Ha M-0.167 mole/L c) Volume (in ml) of 2.00 M Ca(OH)2 solution needed to supply 0.750 mol of Ca(OH)2 VL= VL= 0.750 mole 2.00 M NL= 0.375 L Mb= Vb= 9) Determine the concentration(molarity, M) of each ion present in the following solution: a) 0.25 M NaCl b) 0.25 M K2SO4 b) 0.25 M C6H12O6 Dr. Pahlavan n=(2.00m) (0.0SSL) → [n= 0.110 Mole HNO3) M7VL 10) Calculate the following quantities: Vb Ma мь a) Volume (in ml) of 0.75 M HCl required to neutralized completely 25.0 ml of 0.15 M Ba(OH)2 HCL Ba(OH)2 nap nb= Ma= Va= 2 namava-nbM6V6 b) if 30.0 ml of 0.75 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solution? c) Explain, how would you prepare 500.0 ml of 0.01 M NaOH solution starting with pure solid?
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Ionic Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS