10-5. A 220-V, 1.5-hp, 50-Hz, two-pole, capacitor-start induction motor has the follow- ing main-winding impedances: R = 1.40 2 X, = 1.90 2 XM = 100 2 R2 = 1.502 X2 = 1.90 2 At a slip of 0.05, the motor's rotational losses are 291 W. The rotational losses may be assumed constant over the normal operating range of the motor. Find the fol- lowing quantities for this motor at 5 percent slip: (a) Stator current (b) Stator power factor (c) Input power (d) PAG (e) Pconv

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10-5. A 220-V, 1.5-hp, 50-Hz, two-pole, capacitor-start induction motor has the follow-
ing main-winding impedances:
R = 1.40 2
X = 1.90 2
Хм
= 100 2
%3D
%3D
R2 = 1.502
X2 = 1.902
%3D
At a slip of 0.05, the motor's rotational losses are 291 W. The rotational losses may
be assumed constant over the normal operating range of the motor. Find the fol-
lowing quantities for this motor at 5 percent slip:
(a) Stator current
(b) Stator power factor
(c) Input power
(d) PAG
(e) P.
conv
Transcribed Image Text:10-5. A 220-V, 1.5-hp, 50-Hz, two-pole, capacitor-start induction motor has the follow- ing main-winding impedances: R = 1.40 2 X = 1.90 2 Хм = 100 2 %3D %3D R2 = 1.502 X2 = 1.902 %3D At a slip of 0.05, the motor's rotational losses are 291 W. The rotational losses may be assumed constant over the normal operating range of the motor. Find the fol- lowing quantities for this motor at 5 percent slip: (a) Stator current (b) Stator power factor (c) Input power (d) PAG (e) P. conv
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