(10) 4+31 & Let Trigonometric form of is rcosc +r sin o As such here, rcos = 4 ring = 3 Squaring the two and adding 2 r²(cos ²0+ sinlo] = (4)² + (3) => r = s = 25 Dividing we get, tano = 3 2/1/4 = 4+31 = Hence, Trigonometric for = tań (²/17) a complex number 5 Coso tissino for polar form is ++3² = 5 (Cosm tisino), tan' (²) where @ = tan¹ 0= tan¹ (3)
(10) 4+31 & Let Trigonometric form of is rcosc +r sin o As such here, rcos = 4 ring = 3 Squaring the two and adding 2 r²(cos ²0+ sinlo] = (4)² + (3) => r = s = 25 Dividing we get, tano = 3 2/1/4 = 4+31 = Hence, Trigonometric for = tań (²/17) a complex number 5 Coso tissino for polar form is ++3² = 5 (Cosm tisino), tan' (²) where @ = tan¹ 0= tan¹ (3)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT
Transcribed Image Text:)e(
Let Trigonometric form of
is
r cose + r sin o
As such here,
4+3 ₁
&
rcoso
q
rgin = 3
Squaring the two and adding
2
2
r²(cos ²0+ sin²0) = (4) ²² + (3) ²
2
=>
7
ъв
2
r = 5
Dividing we get,
tano = 3
= 25
->
4+31
4+3i
Hence, Trigonometric form is
tan² (²2/7/)
=
for polar form
5 Coso tissino
" complex number
@?
= 5 (cose +istno),
4+3;=se
where @ = tan!
a
@
Ans
= tań² (²³/1/)
(2)
0 = tan¹ (²)
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