10-43 (modified) Yippee the last HW problem of the semester! A. Determine the moment of inertia of the beam's cross-sectional area about the y-axis. B. Find the product of inertia, Ixy about the given x-y axes. For both parts, use the 3 rectangles shown in your computations and ignore the centroidal axes x'-y' for this problem. == 30 mm 140 mm 30 mm y 30 mm 70 mm 3 170 mm 30 mm x
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- Use the virtual work method to determine the vertical deflection at joint C of the frame shown (you can use either the integration or the figures) Note: BC has I while AB has 21 5 m 11 -32 kN kN/m 3 m 5 m 21 A I - 554 (106) mm* E= constant = 70 GPa 4 m: Consider the blue shaded triangle with a semicircular hole at the top. The figure is not to scale. y 123 тm 37 mm 74 mm a) Determine the moment of inertia around the a-axis of the triangle without the hole. I, mm (for the solid triangle). b) Determine the moment of inertia around the a- axis for the shaded region; i.e. the triangle with the hole. I, mm (for the triangle with the hole).Determine the distance H from the upper surface of the symmetric double-T beam cross section to the location of the centroid. 350 14 -75 H 215 14 Dimensions in millimeters Answer: H = mm %3D
- Calculate the neutral axis in the beam shown in Figure by using the transformed area method, fc = 3000 psi, n = 9, and M = 70 ft-k. 17 in. 20 in. 3 #9 bars (A, = 3.00 in.?) 3 in. 10 in Select one: O a. 6.78 in b. 7.90 in C. 8.25 in d. 7.25 inCalculate the vertical deflection of point B and the horizontal movement at D shown in the figure. Consider that all the elements of the truss are linearly elastic and have sectional areas of 1800mm2. Also consider an E of 200,000N/mm2. Add the calculation process of solving the problem step by step and complete the table accordingly. L F FB ∂FB / ∂PB FD ∂FD/∂PD AE - 2√2/3 PB -2/3 √2 EB EF AB BC CD BF FD FCShould the moment at ED be 256.95? and i am not seeing you calculate that moment at E
- Determine the Deflection at C. Use the Any Geometric Method (once for DIM, once for AMM, once for CBM) E = 200 GPa, I = 250x10° mm“. Distance are in meters. Show complete Solutions 28 kN/m 18 kN |8 kN/m. 15 kN-m A Ов с 10 Technology Drven by (nnovntion FEU ALABANG FEU DLIMAN FEU TECH Input your answer in two decimal places. Units in millimeters. No need to write down the units. Just input the numerical value with the sign. Example: if your final answer is 2.11mm upwards, just key-in 2.11 then if your final answer is 2.11mm downwards, key-in -2.11For the area shown, determine: a) The centroidal coordinates X and Y. b) The moment of inertia about the X and Y axes (IxeIy) . c) The polar moment of inertia about the origin (Jo) . d) The moment centroidal polar of inertia (Jc).Find: Using the Principle of Virtual Work, and with equations for internal bending moment for both the real and virtual systems, calculate the vertical deflection of Point Bof the beam. P C В 0.25L 0.75L
- Solve this problem using Conjugate beam method and Virtual Work method . provide readable complete solution Determine the deflection at point C of the beam shown. E = 200 GPa. I = 250(106) mm4Determine the slope and deflection at point B of the beam ABC shown using the AreaMoment Method. Use E = 200 GPa and I = 1665 x 106 mm4 SUBJECT: THEORY OF STRUCTURES THE SECOND PIC IS MY PROGRESSDraw the M, N, T diagrams of the beam in the figure using the integration method. 8kN 4kN/m 13 A В 3kNm 5m 1.5m