[10] (1) z²+yz + 2, and the point P₁ = (1,– 1,1). Note that P. = Q. GIVEN: The surface : xy + 2xz+z = FIND: The equation of the tangent plane, σ, to so that the point P, is the point of tangency. EXPRESS your answer in the form: O: ax+by+cz = d

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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[10] (1) GIVEN: The surface Q: 2xy + yz² = 7+2xz+z²,
and the point P₁ = (1, 2, 3). Note that P₁ = Q.
FIND: The equation of the tangent plane, o, to
so that the point Po is the point of tangency.
EXPRESS your answer in the form: o: ax+by+ cz = d
METHOD:
Q: 2xy + yz² = 7+2xz+z²
2zJ-2zz +yz² − z² = 7
DEFINE F: R³ R₂
3
F(x, y, z) = 2xy − 2xz+yz²_z²
▼F = (²y-2z, 2x+z²,−2x+2yz−2z)
⇒ VF(1,2,3) = (-2,11,4)
Hence,
O: −2(x-1)+11(7-2) + 4(z-3) = 0
O: 2x +11y + 4z = 32
Transcribed Image Text:[10] (1) GIVEN: The surface Q: 2xy + yz² = 7+2xz+z², and the point P₁ = (1, 2, 3). Note that P₁ = Q. FIND: The equation of the tangent plane, o, to so that the point Po is the point of tangency. EXPRESS your answer in the form: o: ax+by+ cz = d METHOD: Q: 2xy + yz² = 7+2xz+z² 2zJ-2zz +yz² − z² = 7 DEFINE F: R³ R₂ 3 F(x, y, z) = 2xy − 2xz+yz²_z² ▼F = (²y-2z, 2x+z²,−2x+2yz−2z) ⇒ VF(1,2,3) = (-2,11,4) Hence, O: −2(x-1)+11(7-2) + 4(z-3) = 0 O: 2x +11y + 4z = 32
[10] (1)
GIVEN: The surface : xy + 2xz+z
and the point Po= (1,
-
z² + y2 + 2,
1,1). Note that Po € Q
=
FIND: The equation of the tangent plane, o, to
so that the point Po is the point of tangency.
EXPRESS your answer in the form: O: ax+by+cz = d
Transcribed Image Text:[10] (1) GIVEN: The surface : xy + 2xz+z and the point Po= (1, - z² + y2 + 2, 1,1). Note that Po € Q = FIND: The equation of the tangent plane, o, to so that the point Po is the point of tangency. EXPRESS your answer in the form: O: ax+by+cz = d
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