Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
1.Why is Yasmine's work incorrect? Explain your reasoning below.
2. Simplify 2√(7+√8). Show your work?

Transcribed Image Text:**Problem: Simplify**
Simplify \(\sqrt{2} \, (7 + \sqrt{8})\). Show your work.
**Solution:**
To simplify the expression \(\sqrt{2} \, (7 + \sqrt{8})\), we need to use the distributive property.
1. **Distribute \(\sqrt{2}\):**
\(\sqrt{2} \times 7 + \sqrt{2} \times \sqrt{8}\)
- For the first term: \(\sqrt{2} \times 7 = 7\sqrt{2}\)
- For the second term: \(\sqrt{2} \times \sqrt{8} = \sqrt{16}\)
2. **Simplify \(\sqrt{16}\):**
\(\sqrt{16} = 4\)
3. **Final Expression:**
Combine the terms to get the simplified expression:
\(7\sqrt{2} + 4\)
**Conclusion:**
The simplified form of the expression \(\sqrt{2} \, (7 + \sqrt{8})\) is \(7\sqrt{2} + 4\).
![**Yasmine's Work:**
\[
\sqrt{56a^3b}
\]
\[
\sqrt{(2^3)(7)(a^3)(b)}
\]
\[
2a\sqrt{7b}
\]
**Explanation:**
Yasmine is simplifying the expression \(\sqrt{56a^3b}\).
1. **Prime Factorization:** She starts by breaking down 56 into its prime factors: \(2^3 \times 7\).
2. **Expression Breakdown:** She expresses \(56a^3b\) as \((2^3)(7)(a^3)(b)\) under the square root.
3. **Simplification:** Yasmine simplifies this to \(2a\sqrt{7b}\) by taking out perfect squares from under the square root.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf58f763-066e-4899-9645-6f396696042c%2Fa8e61703-9196-4dc9-8535-4bbc41e08b37%2F2wnqtg_processed.png&w=3840&q=75)
Transcribed Image Text:**Yasmine's Work:**
\[
\sqrt{56a^3b}
\]
\[
\sqrt{(2^3)(7)(a^3)(b)}
\]
\[
2a\sqrt{7b}
\]
**Explanation:**
Yasmine is simplifying the expression \(\sqrt{56a^3b}\).
1. **Prime Factorization:** She starts by breaking down 56 into its prime factors: \(2^3 \times 7\).
2. **Expression Breakdown:** She expresses \(56a^3b\) as \((2^3)(7)(a^3)(b)\) under the square root.
3. **Simplification:** Yasmine simplifies this to \(2a\sqrt{7b}\) by taking out perfect squares from under the square root.
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