1.The probability density function of a continuous random variable X is given by f(x) : 04 i) Find k ii) Find P (1.5
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- Which of the following functions are allowable as a probability density function for some continuous random variable? 0 A B D E F A: f₁(x) = C: f3(x) = {8² √3x² −1≤x≤0 else 10 I² x > 10 x < 10 E: f5(x) = 1- B: f₂(x) = D: f4(x) = x² −1 < x < 1 else {50 [5(1-x²)4 0≤x≤ 1 else (8x² - 6x +1) 0≤x≤1 else F: NeitherGiven that the probability density function of the continuous random variable X is given as follows, what is E (6X + 3X²) equal to? f(x)={ 2(1-x), 0<x<1 0, e.w a)15/18 b)5/2 c)1/18 d)1/3Suppose a random variable X has a probability density function given by O elsewhere f (x) = kx (1 − x) 0 ≤ x ≤ 1 0 elsewhere a. Find the value of k that makes this a probability density function b. Find P (0.4 ≤ x ≤ 1) c. Find P(x ≤ 0.4) d. Find P (0.8 ≤ x))
- The PDF of a random variable Y is Sy/2 09 -Probability density function for a continuous random number For 1 <x <3, it is equal to f (x) = (6/32) x +2/16. for other cases, f (x) = 0. Find the cumulative probability function F (x <1 and x = 1) of the continuous probability division. A)1/5 B)0 C)1/2 D)1/4 TO)3/4Let XE {-1,0, 1} . That is, X is a discrete random variable only takes three values -1, 0, and 1. Suppose the equality for Chebyshev's inequality holds for X and P(X = 0) = 0.3 , find P(X = 1) Let X be a random variable with probability density f(x) = x6 for x > 1 and O else. Use Chebyshev's inequality to bound P(X > 2.5) . Round your answer to 3 decimal places.Let X be a random variable with the following probability density function: f (x) = (1 – a2), –1 < x < 1 4 and f (x) = 0 otherwise. Give the integrals for the following: a) The mean b) The variance c) P[ -0.75 < X < 0.5 ]. d) the CDFb) A random variable Xhas probability density function. [Cx(1-x), 0≤x≤1 fx(x) = 3 in) Find [x²] 2 i) Find C. ii) Find P CS Scanned with CamScanner 076, elsewhereThe total number of hours, measured in units of 100 hours, that a family runs a vacuum cleaner over a period of one year is a continuous random variable X that has the density function shown below. Find the probability that over a period of one year, a family runs their vacuum cleaner (a) less than 110 hours; (b) between 55 and 80 hours. f(x) = X, 0a) Let X₁, X₂,..., X, denote a random sample from N (0,0²) distribution with probability density function: f(x; 0²) = 72 -01. Consider a random variable X with probability density function given as: 0 if x < 0, 1 if 0 ≤ x ≤ 1, f(x) 2 1 if 1 < <∞. -2x² Verify if f(x) is indeed a density function. If it is, find the distribution function of X.The probability density function (p.d.f) of the random variable X is given by i) ii) iii) 0≤x≤1 f(x) = {kx(1-x²), otherwise Show that the value of k must be 4 so that f(x) is p.d.f. Calculate P (0 < x <=). Find the values of A so that P(0 < X < A) =SEE MORE QUESTIONSRecommended textbooks for youA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSONA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON