1.Find the exact step counts (growth function) and time complexity for following algorithms - i. ii. iii. 1.Input m and n 2.If m == n 1. Initialize i=0 Algorithm Add(a,b,c,m,n) 1. for i :=1to m do 2. For i=0 to n-1 3. Print "Same" 3. Read an integer in Arr[i] 2. for i:=1to n do 4. For i=0 to n-1 Print Arr[i] 4. Sum=m+n 3. C[ij]:=a[i, j]+b[ij]; 5. Print Sum 5. 6.Else Print “Not same" vi. iv. V. 1. sum = 0 Algorithm Sum (a,n) 1 s:=0.0; 1.int i, j, k = 0; 2. for i = 1 to n: 2.for (i =1; i<= n*n; i++) 3. for j = i to n: for (j = 1; j<= n; j = j+1) k = k + n/2; 3. for i :=1to n do 4. 3 S:=s+a[i]; 4. sum += a[i][j] 4 return s; 5. print(sum) vii. 1. Set i=0 2. Repeat step 3-6 till i<=n 3. viii. ix. 1. Set I=n void fun(int n, int arr[]) 1. { 2. 2. While I>1 int i = 0, j= 0; 3. Set J=n 3. J=1 4. While J>0 for(; i

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1.Find the exact step counts (growth function) and time complexity for following algorithms -
iii.
Algorithm Add(a,b,c,m,n)
1. for i:=1tom do
i.
ii.
1.Input m and n
2.If m == n
1. Initialize i =0
2. For i=0 to n-1
3.
Print "Same"
3.
Read an integer in Arr[i]
2.
for i :=1to n do
4. For i=0 to n-1
Print Arr[i]
4.
Sum=m+n
3.
c[ij]:=a[i, j]+b[ij];
5.
Print Sum
5.
6.Else Print "Not same"
vi.
iv.
v.
1. sum = 0
Algorithm Sum (a,n)
1 s:=0.0;
1.int i, j, k = 0;
2. for i = 1 to n:
2.for (i =1; i<=n*n; i++)
for (j = 1; j <= n; j = j +1)
k = k + n/2;
3.
for j = i to n:
for i :=1to n do
s:=s+a[i];
3.
2
4.
4.
sum += a[i][j]
4 return s;
5. print(sum)
vii.
1. Set i=0
2. Repeat step 3-6 till i<=n
3.
viii.
ix.
void fun(int n, int arr[])
1. {
int i= 0, j= 0;
for(; i<n; ++i)
while(j <n && arr[i] < arr[j])
j+t:
1. Set I =n
2. While I>1
Set J=n
3.
J=1
2.
4.
While J>0
4.
Whilę J<n
3.
5.
J= J/2
5.
K=1
4.
6.
i=i+1
6.
While K <n
5.
7.
K += 2
6. }
8.
J *= 2
9.
I/= 2
Transcribed Image Text:1.Find the exact step counts (growth function) and time complexity for following algorithms - iii. Algorithm Add(a,b,c,m,n) 1. for i:=1tom do i. ii. 1.Input m and n 2.If m == n 1. Initialize i =0 2. For i=0 to n-1 3. Print "Same" 3. Read an integer in Arr[i] 2. for i :=1to n do 4. For i=0 to n-1 Print Arr[i] 4. Sum=m+n 3. c[ij]:=a[i, j]+b[ij]; 5. Print Sum 5. 6.Else Print "Not same" vi. iv. v. 1. sum = 0 Algorithm Sum (a,n) 1 s:=0.0; 1.int i, j, k = 0; 2. for i = 1 to n: 2.for (i =1; i<=n*n; i++) for (j = 1; j <= n; j = j +1) k = k + n/2; 3. for j = i to n: for i :=1to n do s:=s+a[i]; 3. 2 4. 4. sum += a[i][j] 4 return s; 5. print(sum) vii. 1. Set i=0 2. Repeat step 3-6 till i<=n 3. viii. ix. void fun(int n, int arr[]) 1. { int i= 0, j= 0; for(; i<n; ++i) while(j <n && arr[i] < arr[j]) j+t: 1. Set I =n 2. While I>1 Set J=n 3. J=1 2. 4. While J>0 4. Whilę J<n 3. 5. J= J/2 5. K=1 4. 6. i=i+1 6. While K <n 5. 7. K += 2 6. } 8. J *= 2 9. I/= 2
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