1.Determine total uniform loading ( w,) on beam B1. 2.Draw beam loading and label reactions (FBD). 3.Solve for reactions using equilibrium equations (show all work). Factored Loads: Live Load (LL) = 100 PSF Dead Load (DL) = 60 PSF B1 Total Load Combo: (TL) TL = LL+DL 30 5 Equal Spaces

Q: Replace the distributed loading by an equivalent resultant Force. Suppose that wi = 2 kN/m and w2 =…

A: W1=2 KN/m W2=5.5KN/m Length of beam=6m

Q: Consider the overhanging beam shown in the figure below. (Figure 1) Figure ▼ Part A 8 kN/m Tmax= 4 m…

A: An overhanging beam with uniformly distributed load and a point load at the free end.Overall height…

Q: A beam with the cross-section shown is subjected to a vertical shear of 28 kN. Determine: (a) the…

A:

Q: What are appropriate relations established from the calculation of maximum shear stress in a thin…

A:

Q: A beam shown below has a T-shaped cross section. Determine t maximum compressive stress of the beam.…

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.