1.Determine AH° for 2 Al (s) + 3/2 02 (g) → Al203 (s) Given AH° = -286 kJ/mol AH° = -1050 kJ/mol AH° = -238 kJ/mol H2 (g) + ½ 02 (g) → H2O (I) 2 Al (s) + 6 H+ (ag) → 2 Al3+ (ag) + 3 H2 (g) Al203 (s) + 6 H+ (ag) → 2 Al3+ (ag) + 3 H20 (g) 2. Assume a coffee-cup calorimeter had a heat capacity (C) of 420 J/°C. If 1.00 g of Al203 completely reacted with HCI (H+ ) in the calorimeter, calculate the temperature change, AT. Hint: one of the reactions and AH values from question #1 may be helpful. Watch your units! MW (Al203) = 101.96 g/mol

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1.Determine AH° for 2 Al (s) + 3/2 02 (g) → Al203 (s)
Given
H2 (g) + ½ 02 (g) → H2O (I)
AH° = -286 kJ/mol
2 Al (s) + 6 H+ (ag) → 2 A13+ (ag) + 3 H2 (g)
Al203 (s) + 6 H+ (ag) → 2 Al3+ (ag) + 3 H20 (g)
AH° = -1050 kJ/mol
AH° = -238 kJ/mol
2. Assume a coffee-cup calorimeter had a heat capacity (C) of 420 J/°C. If 1.00 g of Al203
completely reacted with HCI (H+ ) in the calorimeter, calculate the temperature change, AT.
Hint: one of the reactions and AH values from question #1 may be helpful. Watch your units!
MW (AI203) = 101.96 g/mol
Transcribed Image Text:1.Determine AH° for 2 Al (s) + 3/2 02 (g) → Al203 (s) Given H2 (g) + ½ 02 (g) → H2O (I) AH° = -286 kJ/mol 2 Al (s) + 6 H+ (ag) → 2 A13+ (ag) + 3 H2 (g) Al203 (s) + 6 H+ (ag) → 2 Al3+ (ag) + 3 H20 (g) AH° = -1050 kJ/mol AH° = -238 kJ/mol 2. Assume a coffee-cup calorimeter had a heat capacity (C) of 420 J/°C. If 1.00 g of Al203 completely reacted with HCI (H+ ) in the calorimeter, calculate the temperature change, AT. Hint: one of the reactions and AH values from question #1 may be helpful. Watch your units! MW (AI203) = 101.96 g/mol
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