1.Calculate the pH of a homogeneous solution which results from the mixing of 0.250M C6H5CO2H(aq) (Benzoic Acid) to a 0.250M C6H5CO2Na(aq) (Sodium Benzoate). Ka (C6H5CO2H) = 6.3x10-5 2. For a electrolytic cell, the cathode has a ________ sign and is the site of ________. 3. Using the following standard reduction potentials: Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Pb2+(aq) + 2 e- → Pb(s) E° = -0.13 V calculate the standard cell potential for the galvanic cell reaction given below, and determine whether or not this reaction is spontaneous under standard conditions. 2 Fe3+(aq) + Pb(s) → Pb2+(aq) + 2 Fe2+(aq
1.Calculate the pH of a homogeneous solution which results from the mixing of 0.250M C6H5CO2H(aq) (Benzoic Acid) to a 0.250M C6H5CO2Na(aq) (Sodium Benzoate). Ka (C6H5CO2H) = 6.3x10-5 2. For a electrolytic cell, the cathode has a ________ sign and is the site of ________. 3. Using the following standard reduction potentials: Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Pb2+(aq) + 2 e- → Pb(s) E° = -0.13 V calculate the standard cell potential for the galvanic cell reaction given below, and determine whether or not this reaction is spontaneous under standard conditions. 2 Fe3+(aq) + Pb(s) → Pb2+(aq) + 2 Fe2+(aq
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1.Calculate the pH of a homogeneous solution which results from the mixing of 0.250M C6H5CO2H(aq) (Benzoic Acid) to a 0.250M C6H5CO2Na(aq) (Sodium Benzoate). Ka (C6H5CO2H) = 6.3x10-5
2. For a electrolytic cell, the cathode has a ________ sign and is the site of ________.
3.
Using the following standard reduction potentials:
|
Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V |
|
Pb2+(aq) + 2 e- → Pb(s) E° = -0.13 V |
calculate the standard cell potential for the galvanic cell reaction given below, and determine whether or not this reaction is spontaneous under standard conditions.
2 Fe3+(aq) + Pb(s) → Pb2+(aq) + 2 Fe2+(aq
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