- 2. From the loading as shown, at whatis fastened bya frictionless pin toa block weighing l0okN as shown in will produce a rotational equilibrium!figure. At vertical wall the Muau= 0.269while under the block the Mblock= 0.20.Oetermine the force Pneeded tostart the moti on to theExercise No 3 Lab.A uniform bar AB weighing 5OOKN,distance (x) from the left supportwhat are the values of R, and Rz?4m2mright.WAFICO KNW500KMbarX=?.18 KNP:18KN/Me = 45°AMolock= 0.2 E. 'k blockC mFNA3mRIRz

Given DataWA=100kNWbar=500kNμkwall=0.268μkblock=0.2θ=45°To findP=? Free Body Diagram ***As per our…

1.A uniform bar AB weighing 5OOKN, is fastened bya frictionless pin to a block weighing 100KN as shown in figure. At vertical wall the Mwa= 0.268 while under the block the Mbuock= 0.20. Determine the force Pneeded to start the moti on to the Awall right. W500k bar Nll e = 45° fx block 0.2 l FNA Molack P.

1.A uniform bar AB weighing 5OOKN, is fastened bya frictionless pin to a block weighing 100KN as shown in figure. At vertical wall the Mwa= 0.268 while under the block the Mbuock= 0.20. Determine the force Pneeded to start the moti on to the Awall right. W500k bar Nll e = 45° fx block 0.2 l FNA Molack P.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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