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1.8 Convert the volume of each of the following to conditions of standard temperature (273 K) and pressure (1 bar = 1.00 × 10° Pa) and give your answer in m³ in each case: (a) 30.0 cm of CO, at 290 K and 101 325 Pa (1 atm)

1.8 Convert the volume of each of the following to conditions of standard temperature (273 K) and pressure (1 bar = 1.00 × 10° Pa) and give your answer in m³ in each case: (a) 30.0 cm of CO, at 290 K and 101 325 Pa (1 atm)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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19.15 Thu 2. Sep * 56 %O T •.. 0+ My Note 12 Table 1.2 Some derived units of the SI system with particular names. 1.8 Convert the volume of each of the following to conditions of standard temperature (273 K) and pressure (1 bar = 1.00 × 10° Pa) and give your Unit Name of unit Symbol Relation to base units answer in m° in each case: Energy joule J kg m² s-2 3 (a) 30.0 cm of CO2 at 290 K and 101 325 Pa (1 atm) Frequency hertz Hz s -2 Force newton N kg ms The nelevant equation is : kg m-ls-2 Pressure pascal Ра S Electric charge coulomb C As Pi Vi P Vz T2 A² s* kg¯' m¯² -1 Capacitance farad F Electromotive force (emf) volt V kg m² s-3 A-! Pe= 15 kg m² s-³ A-2 1.01X10 Pa Resistance ohm Ω PI = 1.00X 10 Pa Vi # ? Ti= 273k Ve = 30cm = 0,00003 m CHEMISTRY %3D = 3 x r0 4th Edition Cl.00xro Pa) x(Vim') (273k) (1.01x10Pa)x (3x10 m) (290 k) -5 H Не Li Be C Ne Na Mg AI Si P CI Ar Cl.00 X10PA)x (290k) Vi = (273k)x CLorX1o Pa)x(3X 10 m) a Sc Ti V Cr Mn Fe Co Cu Zn Ga Ge As Se Br Kr No Tc Ru d Ag Cd In Sn Sb TeI Ri Xe %3D Hf Ta w US Ir P Au Hg TI Pb Bi Po At Rn Ra Rf Db Sgon Hs Mt Ds Rg Uub Uut Uuq Uup Uuh Uuc La Ce Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Ac Th Pa Np Pu Am Cm Bk Cf Es Fm Md No Lr |290 827.19x10°m -3 3 -5 3 V = 0.35028 XIO m Catherine E. Housecroft Supported by Edwin C. Constable MasteringCHEMISTRY My result of the calecelation is not the same as the model answer below. 1.8 (a) 2.86 × 10-5 m³ 10 10 +
Transcribed Image Text:19.15 Thu 2. Sep * 56 %O T •.. 0+ My Note 12 Table 1.2 Some derived units of the SI system with particular names. 1.8 Convert the volume of each of the following to conditions of standard temperature (273 K) and pressure (1 bar = 1.00 × 10° Pa) and give your Unit Name of unit Symbol Relation to base units answer in m° in each case: Energy joule J kg m² s-2 3 (a) 30.0 cm of CO2 at 290 K and 101 325 Pa (1 atm) Frequency hertz Hz s -2 Force newton N kg ms The nelevant equation is : kg m-ls-2 Pressure pascal Ра S Electric charge coulomb C As Pi Vi P Vz T2 A² s* kg¯' m¯² -1 Capacitance farad F Electromotive force (emf) volt V kg m² s-3 A-! Pe= 15 kg m² s-³ A-2 1.01X10 Pa Resistance ohm Ω PI = 1.00X 10 Pa Vi # ? Ti= 273k Ve = 30cm = 0,00003 m CHEMISTRY %3D = 3 x r0 4th Edition Cl.00xro Pa) x(Vim') (273k) (1.01x10Pa)x (3x10 m) (290 k) -5 H Не Li Be C Ne Na Mg AI Si P CI Ar Cl.00 X10PA)x (290k) Vi = (273k)x CLorX1o Pa)x(3X 10 m) a Sc Ti V Cr Mn Fe Co Cu Zn Ga Ge As Se Br Kr No Tc Ru d Ag Cd In Sn Sb TeI Ri Xe %3D Hf Ta w US Ir P Au Hg TI Pb Bi Po At Rn Ra Rf Db Sgon Hs Mt Ds Rg Uub Uut Uuq Uup Uuh Uuc La Ce Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Ac Th Pa Np Pu Am Cm Bk Cf Es Fm Md No Lr |290 827.19x10°m -3 3 -5 3 V = 0.35028 XIO m Catherine E. Housecroft Supported by Edwin C. Constable MasteringCHEMISTRY My result of the calecelation is not the same as the model answer below. 1.8 (a) 2.86 × 10-5 m³ 10 10 +
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