1.4-2 A circular nylon pipe supports a downward load P, = 10 kN, which is uniformly distributed around a cap plate at the top of the lower pipe. A second load Pp = 20 kN is applied upward at the top. The inner and outer diameters of the upper and lower parts of the pipe are d = 50 mm, d, = 60 mm, dz = 55 mm, and d, = 65 mm, respectively. The bot- tom pipe has length 400 mm and the upper pipe has length 300 mm. (a) Calculate the axial normal stress in each pipe segment. (b) Calculate the strain in each pipe segment if the clongation of the upper pipe is 3.29 mm and the elongation of the bottom part is 1.25 mm. PB L1 = 300 mm PA - dz- -d4- L2= 400 mm

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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1.4-2 A circular nylon pipe supports a downward
load P, = 10 kN, which is uniformly distributed
around a cap plate at the top of the lower pipe. A
second load P = 20 kN is applied upward at the
top. The inner and outer diameters of the upper and
lower parts of the pipe are d, = 50 mm, d, = 60 mm,
d, = 55 mm, and d, = 65 mm, respectively. The bot-
tom pipe has length 400 mm and the upper pipe has
length 300 mm.
(a) Calculate the axial normal stress in each pipe
segment.
(b) Calculate the strain in each pipe segment if the
elongation of the upper pipe is 3.29 mm and
the elongation of the bottom part is 1.25 mm.
PB.
Lj = 300 mm
-dz
PA
L2= 400 mm
-dz-
-d4
PROBLEM 1.4-2
Transcribed Image Text:1.4-2 A circular nylon pipe supports a downward load P, = 10 kN, which is uniformly distributed around a cap plate at the top of the lower pipe. A second load P = 20 kN is applied upward at the top. The inner and outer diameters of the upper and lower parts of the pipe are d, = 50 mm, d, = 60 mm, d, = 55 mm, and d, = 65 mm, respectively. The bot- tom pipe has length 400 mm and the upper pipe has length 300 mm. (a) Calculate the axial normal stress in each pipe segment. (b) Calculate the strain in each pipe segment if the elongation of the upper pipe is 3.29 mm and the elongation of the bottom part is 1.25 mm. PB. Lj = 300 mm -dz PA L2= 400 mm -dz- -d4 PROBLEM 1.4-2
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