1.383 moles of lithium react according to the equation below: 2Li(s) + 2H;0() → 2LİOH(aq) + H;(g) (R = 0.0821 atm.L/mol.K] Select the correct operation for calculating the number of moles of H2 : The number of moles of Hz is = • unit = Select the correct operation for calculating the volume of 0.6913 mol of H2 at 1.943 atm and 305 K: The volume of H2 gas produced i * unit - cm3 L Kg g/mL mL

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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1.383 moles of lithium react according to the equation below:
2Li(s) + 2H;0() → 2LİOH(ag) + H;(g)
[R = 0.0821 atm.L/mol.K)
Select the correct operation for calculating the number of moles of H2:
The number of moles of Hz is -
• unit =
Select the correct operation for calculating the volume of 0.6913 mol of H2 at 1.943 atm and 305 K:
The volume of H2 gas produced is =
* unit -
cm3
L
Kg
g/ml.
mL
Transcribed Image Text:1.383 moles of lithium react according to the equation below: 2Li(s) + 2H;0() → 2LİOH(ag) + H;(g) [R = 0.0821 atm.L/mol.K) Select the correct operation for calculating the number of moles of H2: The number of moles of Hz is - • unit = Select the correct operation for calculating the volume of 0.6913 mol of H2 at 1.943 atm and 305 K: The volume of H2 gas produced is = * unit - cm3 L Kg g/ml. mL
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