1.14 About 1860, Maxwell showed that the viscosity of a gas is given by 1 7 = -3 pul, = where p is the density, v the mean molecular speed, and 1, the mean free path. The latter quantity he had earlier shown to be 1 - 1/(√2Ngo2), where is the diameter of the molecule. Loschmidt (1865) used the measured value of n, p(gas), and p(solid) together with Joule's calculated v to determine Ng, the number of molecules per cm³ in a gas at STP. He assumed the molecules to be hard spheres, tightly packed in a solid. Given n = 2.0 x 10-4gcm ¹5¹ for air at STP, p(liquid) 1.0 g cm3, p(gas)≈ 1.0 x 10-³ gcm3, and v 500ms-¹, calculate Ng Answer: 1.14 N, 0.7 x 10¹9. cm
About 1860, Maxwell showed that the viscosity of a gas is given by n= (1/3)*p*v*l, where p is the density, v the mean molecular speed, and l, the mean free path. The latter quantity he had earlier shown to be l = 1/(√2 Ng*o^2), where o is the diameter of the molecule. Loschmidt (1865) used the measured value of n, p(gas), and p(solid) together with Joule's calculated v to determine Ng, the number of molecules per cm^3 in a gas at STP. He assumed the molecules to be hard spheres, tightly packed in a solid. Given n= 2.0 x 10-4 g cm^-1 s^-1 for air at STP, p(liquid)=1.0 g cm^-3, p(gas)≈ 1.0 x 10^-3 g cm^-3, and v≈ 500 m s^-1, calculate Ng Answer: 1.14 N, 0.7 x 10^19 cm^-3
I isolated Ng= 3pv/(sqrt(2)*pi*n*sigma2)
and I tried to find sigma using the density of liquid air and the Molar Mass of air of 28.9 g/mol, sigma=(MolarMass/(Avogadros Number * p))1/3
But i get solutions like 1.28 *1023
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