1.1 What would the 5-day BOD have been if the sample had been incubated at 25°C? 1.2 Would the 5-day BOD be higher at 15°C or at 25°C? Explain your answer without doing any calculations. 1.3 What is the BOD value after 12 days if the test is run at a temperature of 15°C? Use as 1.047.

1.1 What would the 5-day BOD have been if the sample had been incubated at 25°C? 1.2 Would the 5-day BOD be higher at 15°C or at 25°C? Explain your answer without doing any calculations. 1.3 What is the BOD value after 12 days if the test is run at a temperature of 15°C? Use as 1.047.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A wastewater sample was diluted 10% with tap water for conducting BOD Test. The DO content in wastewater sample was 1.2 mg/l and water was 6 mg/l. After 5 days incubation at 20°C, the DO of the sample was 0.5 mg/l. Calculate (i) 5 day BOD of wastewater and (ii) ultimate BOD. Assume K₂0 = 0.12/day. ion:
A company is trying to build a new plant in a location near to a stream. You been asked to find out the impact of the discharged wastewater from the proposed plant on that stream that has characteristics shown in the Table below. The expected plant effluent data is shown in the same Table. Considering K₁=0.23 d¹ and K₂= 0.4 d, what is the DO in the critical point Variable Flow rate (m³/s) Ultimate BOD (mg/L) Stream 0.50 Plant 0.15 19 30 7.84 3.00 (20 20 b) 3.62 mg/L c) 4.86 mg/L d) 5.61 mg/L Dissolved oxygen (mg/L) Temperature (°C) a) 2.53 mg/L
A wastewater sample was diluted 10% with tap water for conducting BOD Test. The DO content in wastewater sample was 1.2 mg/l and water was 6 mg/l. After 5 days incubation at 20°C, the DO of the sample was 0.5 mg/l. Calculate (1) 5 day BOD of wastewater and (ii) ultimate BOD. Assume K₂ = 0.12/day.
Following observations were made on a 4% dilution of wastewater. DO of aerated water used for dilution = 4 mg/1 DO of diluted sample after 5 days of incubation = 0.5 mg/1 DO of original wastewater sample = 0.2 mg/1 What is the value of BOD5 (in mg/1)?
Q- If the BOD3 of a wastewater sample is 75 mg/L and reaction rate constant k (base e) is 0.345 per day, find the amount of BOD remaining in the given sample after 10 days.
Solve quickly
Determine the 5-day BOD for a wastewater sample when 15 ml of wastewater is diluted up to the mark in a 300mL BOD bottle with phosphate buffer. Initial concentration of dissolved O2 = 15 mg/L; Concentration of dissolved O2 on Day 5 = 5 mg/L. BOD5 = (D1 - D5)/p 0.033 mg/L 0.67 mg/L 200 mg/L 100 mg/L
The BODs of a domestic wastewater sample is considered to be about 200 mg/l and the DO in it is measured as 0 mg/L. The laboratory staff are preparing to set up a BOD test to determine the actual BOD of the sample. The DO of the dilution water was measured to be 9 mg/I. Which of the following volume ratios of (total volume of BOD bottle = 300 mL) / (volume of wastewater sample) would be most appropriate to use in setting up the BOD bottle for incubation? Select one among the following: (a) 20/1; (b) 50/1; (c) 100/1; (d) 500/1. Justify your selection
2
A wastewater sample of 2 ml is made up to 300 ml in a BOD bottle with distilled water. The initial D.O. of the sample is 8 mg/l and after 5 days it is 2mg/l. Its BOD is: 1. 6 mg/l 2. 894 mg/l 3. 2400 mg/l 4. 900 mg/l
H Gy Q#4:The table shows data of a wastewater sample collected from a river with a temperature of 30 °C analyzed for the BODs test. The rate constant is 0.2 day-¹ at the lab temperature (20 C). Find BODs at the river. Initial dissolved oxygen, mg/L 9 What will be the BOD7 at the river? Final dissolved oxygen, mg/L 3.5 Sample volume, ml 35
If the BOD3 of a wastewater sample is 75 mg/l and reaction rate constant k (base e) is 0.345 per day, the amount of BOD remaining in the given sample after 10 days is 1. 3.21 mg/L 2. 3.45 mg/L 3. 3.69 mg/L 4. 3.92 mg/L