1.0m 3.0m 0.5m mi PA N, 5. The drawing above shows two objects on a board supported at two locations. The m; = 40 kg (centered over P), m;=20 kg and m3=10 kg. c. Determine the force exerted by N2. (Take torques around P.) d. m2 rolls to the right. Just before the board starts to tip everything is balanced on N2 with no force on N1. Determine how far to the right of N2 m2 could roll without the board tipping. You might find it easier to take torques around a point rather than P.

1.0m 3.0m 0.5m mi PA N, 5. The drawing above shows two objects on a board supported at two locations. The m; = 40 kg (centered over P), m;=20 kg and m3=10 kg. c. Determine the force exerted by N2. (Take torques around P.) d. m2 rolls to the right. Just before the board starts to tip everything is balanced on N2 with no force on N1. Determine how far to the right of N2 m2 could roll without the board tipping. You might find it easier to take torques around a point rather than P.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

1.0m
3.0m
0.5m
mi
m2
PA
N,
5. The drawing above shows two objects on a board supported at two locations. The m; = 40 kg (centered over P), m;=20 kg and m3=10 kg.
c. Determine the force exerted by N2. (Take torques around P.)
d. m2 rolls to the right. Just before the board starts to tip everything is balanced on N2 with no force on N1. Determine how far to the right of N2
m2 could roll without the board tipping. You might find it easier to take torques around a point rather than P.

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