(1.056 x 109) e - 0.55t In In (f'(t)) %3D (1+ 600 e - 0.55t) 2

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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I found the derivative of a limited growth function, and I need to find the second derivative. I know I need to take the natural log of both sides but I'm not sure how to do this. I have a photo attached of where the equation is at. Thank you!

### Mathematical Expression Analysis

The expression given is:

\[ 
\ln (f'(t)) = \ln \left( \frac{(1.056 \times 10^9) e^{-0.55t}}{(1 + 600 e^{-0.55t})^2} \right) 
\]

#### Explanation:

- **Natural Logarithm (\(\ln\))**: The expression involves the natural logarithm of the derivative of a function \(f\) with respect to \(t\), denoted as \(f'(t)\).

- **Exponential Term**: The function includes an exponential decay term \(e^{-0.55t}\), which suggests a process that decreases over time.

- **Numerator**: The term \((1.056 \times 10^9) e^{-0.55t}\) in the numerator suggests multiplication of a constant with an exponentially decaying function.

- **Denominator**: The denominator has \((1 + 600 e^{-0.55t})^2\), indicating the presence of an exponential term raised to the power of 2. The coefficient 600 also multiplies the exponential function.

This expression could represent a variety of real-world phenomena, such as modeling decay processes or population dynamics, where the growth or decay rate changes over time. The presence of a squared term in the denominator suggests some form of damping or friction effect that increases with time.
Transcribed Image Text:### Mathematical Expression Analysis The expression given is: \[ \ln (f'(t)) = \ln \left( \frac{(1.056 \times 10^9) e^{-0.55t}}{(1 + 600 e^{-0.55t})^2} \right) \] #### Explanation: - **Natural Logarithm (\(\ln\))**: The expression involves the natural logarithm of the derivative of a function \(f\) with respect to \(t\), denoted as \(f'(t)\). - **Exponential Term**: The function includes an exponential decay term \(e^{-0.55t}\), which suggests a process that decreases over time. - **Numerator**: The term \((1.056 \times 10^9) e^{-0.55t}\) in the numerator suggests multiplication of a constant with an exponentially decaying function. - **Denominator**: The denominator has \((1 + 600 e^{-0.55t})^2\), indicating the presence of an exponential term raised to the power of 2. The coefficient 600 also multiplies the exponential function. This expression could represent a variety of real-world phenomena, such as modeling decay processes or population dynamics, where the growth or decay rate changes over time. The presence of a squared term in the denominator suggests some form of damping or friction effect that increases with time.
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