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1. y= c,e* +c,e¯*.(-00,00); y'"'–y = 0, y(0) = 0, y'(0) = 1 2. y = c,e*" +c,e",(-0,00); y"-3y'-4y = 0, y(0)= 1, y'(0)= 2 3. y = c,x+c,xln x, (0, 0); x²y"-xy'+y = 0, y(1)= 3, y'(1)= -1 4.x %3D

1. y= c,e* +c,e¯*.(-00,00); y'"'–y = 0, y(0) = 0, y'(0) = 1 2. y = c,e*" +c,e",(-0,00); y"-3y'-4y = 0, y(0)= 1, y'(0)= 2 3. y = c,x+c,xln x, (0, 0); x²y"-xy'+y = 0, y(1)= 3, y'(1)= -1 4.x %3D

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In problems 1-4 the given family of functions is the general solution of the DE on the indicated interval. Find a member of the family that is a solution of the initial-value problem. 1. y = c,e* +c,e¯*.(-00,00); y'"'–y = 0, y(0) = 0, y'(0) = 1 2. y=c,e** +c,e*,(-∞,); y"-3y'-4y = 0, y(0) = 1, y'(0) = 2 3. y= c,x+c,xIn x, (0, 0); x² y'"-xy'+y = 0, y(1)= 3, y'(1) =-1 4. y = c, +c, cos x+ c, sin x, (- ∞, ); y'"'+y'= 0, y(r)= 2, y'"(r)= –1 %3D
Transcribed Image Text:In problems 1-4 the given family of functions is the general solution of the DE on the indicated interval. Find a member of the family that is a solution of the initial-value problem. 1. y = c,e* +c,e¯*.(-00,00); y'"'–y = 0, y(0) = 0, y'(0) = 1 2. y=c,e** +c,e*,(-∞,); y"-3y'-4y = 0, y(0) = 1, y'(0) = 2 3. y= c,x+c,xIn x, (0, 0); x² y'"-xy'+y = 0, y(1)= 3, y'(1) =-1 4. y = c, +c, cos x+ c, sin x, (- ∞, ); y'"'+y'= 0, y(r)= 2, y'"(r)= –1 %3D
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