1. x 1, y 3. x sin2 0, y = cos? 0 2. x D /t, y = 4 - t Parametric Equations 21. x = t2 -t+ 2, y = 4. x = = 2e°, y = e-/2 In Exercises 5-14, find dy|dx and d?yldx², and find the slope 22. x = 4 cos 0, y = 3 sin and concavity (if possible) at the given value of the parameter. In Exercises 23-26, find point where the curve e Point Parametric Equations 5. x = 4t, y = 3t - 2 6. x = /t, y = 3t – 1 7. x = t + 1, y = t² + 3t 8. x = t2 + 5t + 4, y = 4t t = 3 23. x = 2 sin 2t, y 24. x = 2- TT cos t, %3D t = 1 %3D 25. x = - t, y = t = - 1 26. x = t - 6t, y %3D t = 0 In Exercises 27 an vertical tangency TT 9. x = 4 cos 0, y = 4 sin 0 4 27. Involute of a 10. x = cos 0, y = 3 sin 0 x = cos 0 + 6. y = sin 0 11. x = 2 + sec 0, y = 1 + 2 tan 0 t = 2 12. x = Ji, y = Ji – 1 6. 13. x = cos 0, y = sin³ 0 %3D cos e 14 r= A - sin 0. y = 1- II
1. x 1, y 3. x sin2 0, y = cos? 0 2. x D /t, y = 4 - t Parametric Equations 21. x = t2 -t+ 2, y = 4. x = = 2e°, y = e-/2 In Exercises 5-14, find dy|dx and d?yldx², and find the slope 22. x = 4 cos 0, y = 3 sin and concavity (if possible) at the given value of the parameter. In Exercises 23-26, find point where the curve e Point Parametric Equations 5. x = 4t, y = 3t - 2 6. x = /t, y = 3t – 1 7. x = t + 1, y = t² + 3t 8. x = t2 + 5t + 4, y = 4t t = 3 23. x = 2 sin 2t, y 24. x = 2- TT cos t, %3D t = 1 %3D 25. x = - t, y = t = - 1 26. x = t - 6t, y %3D t = 0 In Exercises 27 an vertical tangency TT 9. x = 4 cos 0, y = 4 sin 0 4 27. Involute of a 10. x = cos 0, y = 3 sin 0 x = cos 0 + 6. y = sin 0 11. x = 2 + sec 0, y = 1 + 2 tan 0 t = 2 12. x = Ji, y = Ji – 1 6. 13. x = cos 0, y = sin³ 0 %3D cos e 14 r= A - sin 0. y = 1- II
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How cab I do excercise 11, im stuck just before I substitude with pi/6 on dy/dx for the slope. Im left with (its theta but for writing the question I'll use x) dy/dx = 2sec(x) csc(x)
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