1. Write C++ code for Gaussian elimination method and solves the following electric circuit equations. Note: you can apply Partial Pivoting
1. Write C++ code for Gaussian elimination method and solves the following electric circuit equations. Note: you can apply Partial Pivoting
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![1. Write C++ code for Gaussian elimination method and solves the following electric circuit
equations.
Note: you can apply Partial Pivoting
a. Node voltages in the circuit is given as
upemoce
[9.6 45 -5.6v,
[240]
5
-12 v2 =
200 1
1
-2
4
Using Gaussian elimination, find V1, V2 and V3 values.
b. Node voltages in the circuit is given as
Loop 3
60
2 -5 -16 V2
5
1
-1
-2
V,
"20 V
4
3
-1
-2
V3
10A
10
-2 -1
1
2
20
Loop2
Loop 1
Using Gaussian elimination, find V1, V2 , V3 and Va values.
c. The mesh-current equations for the circuit is given as
50 L
[150 -40 0
-80
30
200 a
-40
65
-30 -15
12 V
-30
50
-20 || i
=|-12
20a
-80 -15
95
20
0 - 20
80 || i,
-20
20 V
Using Gaussian elimination, find the current values.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57116ad4-8874-40a1-882e-548dcc544d7e%2Fefe925ce-4a7b-40c3-89bc-613128bd5a8e%2Fmxkurmj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Write C++ code for Gaussian elimination method and solves the following electric circuit
equations.
Note: you can apply Partial Pivoting
a. Node voltages in the circuit is given as
upemoce
[9.6 45 -5.6v,
[240]
5
-12 v2 =
200 1
1
-2
4
Using Gaussian elimination, find V1, V2 and V3 values.
b. Node voltages in the circuit is given as
Loop 3
60
2 -5 -16 V2
5
1
-1
-2
V,
"20 V
4
3
-1
-2
V3
10A
10
-2 -1
1
2
20
Loop2
Loop 1
Using Gaussian elimination, find V1, V2 , V3 and Va values.
c. The mesh-current equations for the circuit is given as
50 L
[150 -40 0
-80
30
200 a
-40
65
-30 -15
12 V
-30
50
-20 || i
=|-12
20a
-80 -15
95
20
0 - 20
80 || i,
-20
20 V
Using Gaussian elimination, find the current values.
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