1. Write balanced net ionic equations for the following reactions: a) The precipitation of the chloride of Hg22+ in Step 1. b) The formation of a yellow precipitate in Step 3. c) The formation of a black precipitate in Step 4. d) The reaction that occurs in Step 5. Step 4: Separation and Identification of Hg22+. Locate the test tube containing the precipitate saved from Step 2. Add 1 ml of 6 M NH3 (may be labeled as NH¼OH) and stir thoroughly. Centrifuge and then decant the liquid into another clean, dry test tube and save for Step 5. If Hg22+ is present, a gray or black precipitate produced by the reaction of Hg2Cl2 with ammonia willI be observed.

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Balanced net ionic equation of c)

1. Write balanced net ionic equations for the following reactions:
a) The precipitation of the chloride of Hg22+ in Step 1.
b) The formation of a yellow precipitate in Step 3.
c) The formation of a black precipitate in Step 4.
d) The reaction that occurs in Step 5.
Transcribed Image Text:1. Write balanced net ionic equations for the following reactions: a) The precipitation of the chloride of Hg22+ in Step 1. b) The formation of a yellow precipitate in Step 3. c) The formation of a black precipitate in Step 4. d) The reaction that occurs in Step 5.
Step 4: Separation and Identification of Hg22+.
Locate the test tube containing the precipitate saved from Step 2. Add 1 ml of 6 M NH3 (may be
labeled as NH¼OH) and stir thoroughly. Centrifuge and then decant the liquid into another clean,
dry test tube and save for Step 5. If Hg22+ is present, a gray or black precipitate produced by the
reaction of Hg2Cl2 with ammonia willI be observed.
Transcribed Image Text:Step 4: Separation and Identification of Hg22+. Locate the test tube containing the precipitate saved from Step 2. Add 1 ml of 6 M NH3 (may be labeled as NH¼OH) and stir thoroughly. Centrifuge and then decant the liquid into another clean, dry test tube and save for Step 5. If Hg22+ is present, a gray or black precipitate produced by the reaction of Hg2Cl2 with ammonia willI be observed.
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