1. Write and run the following SQL statements 1 CREATE TABLE race ( race_id INT AUTO_INCREMENT NOT NULL, racetrack_id INT NOT NULL, VARCHAR (250) CHARACTER SET utf8mb4 NOT NULL, name 5 date DATE NOT NULL, PRIMARY KEY (race_id), FOREIGN KEY (racetrack_id) REFERENCES racetrack(racetrack_id) Output: 2. In the race table INSERT a few values: Hint as below: INSERT INTO racetrack (name, city) VALUES ("Red Bull Ring", "Spielberg"), ("Hungaroring", "Budapest"); SELECT 4.
1. Write and run the following SQL statements 1 CREATE TABLE race ( race_id INT AUTO_INCREMENT NOT NULL, racetrack_id INT NOT NULL, VARCHAR (250) CHARACTER SET utf8mb4 NOT NULL, name 5 date DATE NOT NULL, PRIMARY KEY (race_id), FOREIGN KEY (racetrack_id) REFERENCES racetrack(racetrack_id) Output: 2. In the race table INSERT a few values: Hint as below: INSERT INTO racetrack (name, city) VALUES ("Red Bull Ring", "Spielberg"), ("Hungaroring", "Budapest"); SELECT 4.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please send screen shots of the out putted values and code please, it keeps throwing me a syntex error in the 1st question by "(race_id)" please do all 4 questions

Transcribed Image Text:Output:
1.1
Racetrack
Race
hosts
RacetrackD (PK)
RacelD (PK)
3.
Name
Racetraco (FK)
City
Name
Date
1.
INSERT INTO race (racetrack_id, name, date)
Figure 72. Related table: Race
2
VALUES (1, "Austria 2020", "2020-07-05"),
1. Write and run the following SQL statements
(2, "Hungary 2020", "2020-07-19");
4
1•e CREATE TABLE race (
5.
SELECT.
2
race_id
INT AUTO_INCREMENT NOT NULL,
6
FROM race3
3
racetrack_id
INT NOT NULL,
VARCHAR (250) CHARACTER SET utf8mb4 NOT NULL,
name
UPDATE race
date
DATE NOT NULL,
PRIMARY KEY (race_id),
2
SET date = "2020-07-12"
6
NHERE race_id - 23
7
FOREIGN KEY (racetrack_id) REFERENCES racetrack(racetrack_id)
3
8 );
Output:
Output
4.
2. In the race table INSERT a few values:
Hint as below:
SELECT
INSERT INTO racetrack (name, city)
2
FROM race
1.
WHERE race_id - 33
VALUES ("Red Bull Ring", "Spielberg"),
3
("Hungaroring", "Budapest");
4.
Output:
SELECT *
FROM racetrack
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