1. Write an equation, in slope-intercept form, for the line graphed below. 3. Graph the line y =x+2 y 4 -6-5-4-3-2-1. 12 34 5 6 -6 -5-4-3-2-1, 1234 5 6 -2- -21 -3 -5+ -6 1. 2. Graph the line y = -2x+3 4. Write an equation, in slope-intercept form, for the line graphed below. 664 321 65 ENT 59 54 321

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Transcription and Explanation for Educational Website**

### Transcription

**1. Write an equation, in slope-intercept form, for the line graphed below.**

- The graph displays a line that intersects the y-axis at 5 and appears to have a negative slope, suggesting a decrease as the line moves from left to right.

**2. Graph the line \( y = -2x + 3 \).**

**3. Graph the line \( y = \frac{4}{5}x + 2 \).**

**4. Write an equation, in slope-intercept form, for the line graphed below.**

### Graph Descriptions and Analysis

#### Diagram 1: Line Graph from Activity 1
- The graph is presented on a coordinate plane with x-axis and y-axis both ranging from -6 to 6.
- The plotted line starts from the point (0, 5) on the y-axis, indicating the y-intercept.
- Points plotted on the line: (-3, 7), (0, 5), (3, 3).
- The line shows a downward trend, indicating the slope is negative. For the given points, it seems the slope \( m \) can be calculated using the formula \( m = \frac{\Delta y}{\Delta x} \) between any two points.

#### Diagram 2: Line Graph from Activity 3
- Similarly presented on a coordinate plane from -6 to 6 on both axes.
- The task involves graphing a line for the equation \( y = \frac{4}{5}x + 2 \).
- To graph this, start at the y-intercept (0, 2) and use the slope \( \frac{4}{5} \) to identify another point by rising 4 units and running 5 units to the right.

This transcription and analysis should help students understand how to interpret and create linear graphs using slope-intercept form.
Transcribed Image Text:**Transcription and Explanation for Educational Website** ### Transcription **1. Write an equation, in slope-intercept form, for the line graphed below.** - The graph displays a line that intersects the y-axis at 5 and appears to have a negative slope, suggesting a decrease as the line moves from left to right. **2. Graph the line \( y = -2x + 3 \).** **3. Graph the line \( y = \frac{4}{5}x + 2 \).** **4. Write an equation, in slope-intercept form, for the line graphed below.** ### Graph Descriptions and Analysis #### Diagram 1: Line Graph from Activity 1 - The graph is presented on a coordinate plane with x-axis and y-axis both ranging from -6 to 6. - The plotted line starts from the point (0, 5) on the y-axis, indicating the y-intercept. - Points plotted on the line: (-3, 7), (0, 5), (3, 3). - The line shows a downward trend, indicating the slope is negative. For the given points, it seems the slope \( m \) can be calculated using the formula \( m = \frac{\Delta y}{\Delta x} \) between any two points. #### Diagram 2: Line Graph from Activity 3 - Similarly presented on a coordinate plane from -6 to 6 on both axes. - The task involves graphing a line for the equation \( y = \frac{4}{5}x + 2 \). - To graph this, start at the y-intercept (0, 2) and use the slope \( \frac{4}{5} \) to identify another point by rising 4 units and running 5 units to the right. This transcription and analysis should help students understand how to interpret and create linear graphs using slope-intercept form.
**Lesson on Graphing Lines and Slope-Intercept Form**

1. **Graphing the Equation \( y = -2x + 3 \)**

   - **Objective:** To graph the linear equation \( y = -2x + 3 \).

   - **Equation Description:** This equation is in slope-intercept form, \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, the slope \( m \) is -2, and the y-intercept \( b \) is 3.

   - **Graph Explanation:**
     - A grid is presented with x and y axes. The graph is centered at the origin (0,0) with axes extending from -6 to 6.
     - The line begins at the y-intercept, (0, 3), and descends with a slope of -2, meaning for each unit increase in x, y decreases by 2.

2. **Writing an Equation for the Graphed Line**

   - **Objective:** To write the equation in slope-intercept form for the given line.

   - **Graph Description:**
     - The graph shows a line passing through points approximately at (0, -2) and (4, 2).
     - From these points, calculate the slope \( m = \frac{\Delta y}{\Delta x} = \frac{2 - (-2)}{4 - 0} = \frac{4}{4} = 1 \).
     - The y-intercept \( b \) is -2, as the line crosses the y-axis at (0, -2).

   - **Equation:** The equation of the line is \( y = x - 2 \).

**Conclusion:** Understanding the components of a linear equation and plotting them accurately demonstrates how graphing works and highlights the relationship between algebraic representation and graphical interpretations.
Transcribed Image Text:**Lesson on Graphing Lines and Slope-Intercept Form** 1. **Graphing the Equation \( y = -2x + 3 \)** - **Objective:** To graph the linear equation \( y = -2x + 3 \). - **Equation Description:** This equation is in slope-intercept form, \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, the slope \( m \) is -2, and the y-intercept \( b \) is 3. - **Graph Explanation:** - A grid is presented with x and y axes. The graph is centered at the origin (0,0) with axes extending from -6 to 6. - The line begins at the y-intercept, (0, 3), and descends with a slope of -2, meaning for each unit increase in x, y decreases by 2. 2. **Writing an Equation for the Graphed Line** - **Objective:** To write the equation in slope-intercept form for the given line. - **Graph Description:** - The graph shows a line passing through points approximately at (0, -2) and (4, 2). - From these points, calculate the slope \( m = \frac{\Delta y}{\Delta x} = \frac{2 - (-2)}{4 - 0} = \frac{4}{4} = 1 \). - The y-intercept \( b \) is -2, as the line crosses the y-axis at (0, -2). - **Equation:** The equation of the line is \( y = x - 2 \). **Conclusion:** Understanding the components of a linear equation and plotting them accurately demonstrates how graphing works and highlights the relationship between algebraic representation and graphical interpretations.
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